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nekit [7.7K]
3 years ago
11

Please help. I will give brainliest!

Mathematics
1 answer:
Andrej [43]3 years ago
7 0

Answer:

Step-by-step explanation:

How to Find Outliers Using the Interquartile Range(IQR)

Step 1: Find the IQR, Q1(25th percentile) and Q3(75th percentile). ...

Step 2: Multiply the IQR you found in Step 1 by 1.5: ...

Step 3: Add the amount you found in Step 2 to Q3 from Step 1: ...

Step 3: Subtract the amount you found in Step 2 from Q1 from Step 1:

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If f(x) = V7x + 31 , find f(0).
Arte-miy333 [17]

Answer:

f(0) = 31

Step-by-step explanation:

We are given the following function:

f(x) = \sqrt{7x} + 31

f(0).

This is the value of f when x = 0. So

f(0) = \sqrt{7*0} + 31 = \sqrt{0} + 31 = 0 + 31 = 31

So f(0) = 31

3 0
3 years ago
Pls help asap! It’s due in one hour!!
AfilCa [17]
1. t = 7
2. t = 0
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8 0
2 years ago
a small rocket is shot from the edge of a cliff suppose that after t seconds the rocket is y meters above the cliff where y=30t-
Natalka [10]

Answer:

Greatest height: 45 meters

Time for greatest height: 3 seconds

Height after 5 seconds: 25 meters above the cliff

Time for height of 40 meters: 7.123 seconds

Height after 7 seconds: -35 meters (35 meters below the cliff)

Step-by-step explanation:

to find the maximum height, we need to calculate the derivative of y in relation to t and then find when dy/dt = 0:

dy/dt = 30 - 10t = 0

10t = 30

t = 3 seconds

In this time, the height is:

y = 30*3 - 5*3^2 = 45 meters

After 5 seconds, the height is:

y = 30*5 - 5*5^2 = 25 meters

The time for the height of 40 meters is:

40 = 30t - 5t^2

t^2 - 6t - 8 = 0

Using Bhaskara's formula, we have:

Delta = 6^2 + 4*8 = 68

sqrt(Delta) = 8.246

t1 = (6 + 8.246) / 2 = 7.123 seconds

t2 = (6 - 8.246) / 2 = -1.123 seconds (negative value for time is not valid)

So the time when the rocket reaches 40 meters is 7.123 seconds

After 7 seconds, the height is:

y = 30*7 - 5*7^2 = -35 meters

The rocket will be 35 meters below the cliff.

5 0
3 years ago
Solve the absolute value equation. <br><br>|x| = –15
lisov135 [29]
|x|=-15\ \ FALSE\ x\in\O\\\\because\ |x|\geq0\ for\ every\ x\in\mathbb{R}.
7 0
3 years ago
PLEASE HELP! ASAP! no links please
adoni [48]
From left to right it’s 1, 49, 9, 70
7 0
3 years ago
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