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Anarel [89]
3 years ago
15

Answer!!!!!! Please!!!!!!

Mathematics
2 answers:
Len [333]3 years ago
7 0

For this case we must resolve the following expression:

2 ^ {\sqrt {19}}

We have by definition:\sqrt {19} = 4.35889894354

Now, rewriting the expression we have:

2 ^ {4,35889894354} = 20,51914828

If we round the expression we have:

2 ^ {\sqrt {19}} = 20.5191

Answer:

Option C

shusha [124]3 years ago
6 0

Answer:

C

Step-by-step explanation:

Using calculator to evaluate

2^{\sqrt{19} } ≈ 20.5191 → C

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3 years ago
15=1/2+3/2x+10
enot [183]

Answer:

x = 1/3

Step-by-step explanation:

15 = 1/2 + 3/2x + 10

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MakcuM [25]

Answer:

p = 4

Step-by-step explanation:

Given equation:

x^2+(p-3)y^2-4x+6y-16=0

<u>Standard equation of a circle:</u>

(x-a)^2+(y-b)^2=r^2

(where (a,b) is the centre of the circle, and r is the radius)

If you expand this equation, you will see that the coefficient of y^2 is always one.

Therefore, p-3=1

\implies p=1+3=4

<u>Additional information</u>

To rewrite the given equation in the standard form:

\implies x^2+y^2-4x+6y-16=0

\implies x^2-4x+y^2+6y=16

\implies (x-2)^2-4+(y+3)^2-9=16

\implies (x-2)^2+(y+3)^2=16+4+9

\implies (x-2)^2+(y+3)^2=29

So this is a circle with centre (2, -3) and radius √29

3 0
2 years ago
What are the possible values of remainder r, when a positive integer 'a' is divided by 3​
fredd [130]

Answer:

0, 1, 2

Step-by-step explanation:

Euclid's division Lemma states that for any two positive integers ‘a’ and ‘b’ there exist two unique whole numbers ‘q’ and ‘r’ such that , a = bq + r, where 0≤ r < b.

Here, a= Dividend, b= Divisor, q= quotient and r = Remainder.

According to Euclid's division lemma a 3q+r, where 0≤r≤3 and r is an integer.

Therefore, the values of r can be 0, 1 or 2.

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3 years ago
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Alika [10]

Answer:

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Step-by-step explanation:

4 0
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