Answer:
Θ = 46°
Step-by-step explanation:
the angle between a tangent and a radius at the point of contact is 90° , so
∠ ABO = 90°
since OB = OD ( radii of circle ) then Δ BOD is isosceles and
∠ OBD = ∠ ODB = 22°
the exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.
∠ AOB is an exterior angle of the triangle , then
∠ AOB = 22° + 22° = 44°
the sum of the 3 angles in Δ AOB = 180° , then
Θ + 44° + 90° = 180°
Θ + 134° = 180° ( subtract 134° from both sides )
Θ = 46°
Answer:
b
Step-by-step explanation:
Answer:
{-1, 4}
Step-by-step explanation:
In the given f(x) = -1/2x^2 + 3/2x - 2
set f(x) = 0 and then multiply all the numeric terms by -2 to remove the fractions:
f(x) = -1/2x^2 + 3/2x - 2 = 0 => 1x^2 - 3x - 4 = 0
This factors into (x - 4)(x + 1) = 0, whose roots are {-1, 4}. These are the zeros.
Median-5
lower quartile-4
upper quartile-7