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3 years ago

Find the measure of each interior angle

Mathematics

1 answer:

prohojiy [21]3 years ago

7 0

L=100, M=110, P=80, N=70

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Select the correct answer. Every dimension of a triangular pyramid is multiplied by 10 to produce a new figure that is geometric

BaLLatris [955]

Answer:

C. The surface area of the pyramid is multiplied by 100

Step-by-step explanation:

The area is the function of the two dimensions.

If each dimension has changed by 10 times, the the area will change by:

10*10 = 100 times

Correct choice is C

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3 years ago

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50 POINTS PLS HELP!!!

densk [106]

Answer:

Do I answer these all or just one?

Step-by-step explanation:

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3 years ago

Which of the following triangle lengths form right triangles? Select all that apply

Mashutka [201]

Answer:

B,C,D

Step-by-step explanation:

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3 years ago

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Suppose a family has three children of different ages. We assume that all combinations of boys and girls are equally likely. (a)

Ivan

Answer:

a) There are 8 possible combinations and each probability is 1/8.

b) The probability that it is a boy given that there are two girls is 3/8

Step-by-step explanation:

a) The sample space is given by:

BBB (3 boys)

BBG (Boy, boy, girl)

BGB (Boy, girl, boy)

BGG (Boy, girl, girl)

GBB (girl, boy, boy)

GBG (girl, boy, girl)

GGB (girl, girl, boy)

GGG (3 girls)

The probability of each combination is the same:

P(BBB)=P(B∩B∩B)= $\frac{1}{2} \frac{1}{2} \frac{1}{2}=\frac{1}{8}$

2) There are three possible combinations in which there are 2 girls and 1 boy:

BGG, GBG, GGB

So the probability is given by:

P(BGG ∪ GBG ∪ GGB)= $\frac{1}{2} \frac{1}{2} \frac{1}{2}+\frac{1}{2} \frac{1}{2} \frac{1}{2}+\frac{1}{2} \frac{1}{2} \frac{1}{2}=\frac{3}{8}$

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3 years ago

A principle of $3100 is invested at 6.5% interest, compounded annually. How much will the investment be worth after 12 years?

Tpy6a [65]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$3100\\ r=rate\to 6.5\%\to \frac{6.5}{100}\dotfill &0.065\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &12 \end{cases} \\\\\\ A=3100\left(1+\frac{0.065}{1}\right)^{1\cdot 12}\implies A=3100(1.065)^{12}\implies A\approx 6600.198$

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