at the beginning of year 4, only 3 years have elapsed, the 4th year hasn't started yet, since it's at the beginning, so at the beginning of year 4 we can say only 4-1 years have elapsed.

![A=700\left( 1 + \frac{0.05}{1} \right)^{1\cdot 3}\implies A = 700(1+0.05)^3\implies A(4)=700(1+0.05)^{4-1} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill A(n)=700(1+0.05)^{n-1}~\hfill](https://tex.z-dn.net/?f=A%3D700%5Cleft%28%201%20%2B%20%5Cfrac%7B0.05%7D%7B1%7D%20%5Cright%29%5E%7B1%5Ccdot%203%7D%5Cimplies%20A%20%3D%20700%281%2B0.05%29%5E3%5Cimplies%20A%284%29%3D700%281%2B0.05%29%5E%7B4-1%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20A%28n%29%3D700%281%2B0.05%29%5E%7Bn-1%7D~%5Chfill)
If a number's ten digit is
and the units digit is
, then you can write the number as
.
Obviously, inverting the digits would lead to the number
.
Since this new number is 36 less than the original, we have

Since we also know that the digit in the tens place is three times that in the units place, we can add an equation to form a system:

And thus 
Answer:
False
Step-by-step explanation:
& is greater that 7 because you are going back to the nmber like in the negatives