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elena55 [62]
3 years ago
14

Does someone know the answer

Mathematics
2 answers:
horrorfan [7]3 years ago
6 0
The answer is B. 340. If it helps, always seperate the shape into other rectangles and find the areas, and add them together at the end.
Naya [18.7K]3 years ago
4 0
The answer is 340 units
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1/3 divided by 3 1/2
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Step-by-step explanation:

8 0
2 years ago
Select all the expressions that are equivalent to (2)^n+³
eimsori [14]

Answer:

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

Step-by-step explanation:

Let us revise some rules of exponent

  • a^{m} × a^{m}  = a^{m+n}
  • (a^{m})^{n} = a^{m*n}

Now let us find the equivalent expressions of  (2)^{n+3}

A.

∵ 4 = 2 × 2

∴ 4 =  2^{2}

∴  (4)^{n+2} =  (2^{2})^{n+2}

- By using the second rule above multiply 2 and (n + 2)

∵ 2(n + 2) = 2n + 4

∴  (4)^{n+2} =  (2)^{2n+4}  

B.

∵ 4 = 2 × 2

∴ 4 =  2²

∴  4(2)^{n+1} = 2² ×  (2)^{n+1}

- By using the first rule rule add the exponents of 2

∵ 2 + n + 1 = n + 3

∴   4(2)^{n+1} =  (2)^{n+3}

C.

∵ 8 = 2 × 2 × 2

∴ 8 =  2³

∴  8(2)^{n} = 2³ ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 3 + n = n + 3

∴  8(2)^{n} =  (2)^{n+3}

D.

∵ 16 = 2 × 2 × 2 × 2

∴ 16 = 2^{4}

∴  16(2)^{n} = 2^{4}  ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 4 + n = n + 4

∴  16(2)^{n} =  (2)^{n+4}

E.

(2)^{2n+3} is in its simplest form

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

3 0
3 years ago
Find the perimeter of a triangle with vertices A(3, 1), B(2, -1), and C(-3, 2). Leave
natulia [17]

The perimeter of triangle is: 14.15 units

Step-by-step explanation:

First of all we have to find the lengths of sides of triangles

Given

A(3, 1), B(2, -1), and C(-3, 2)

The distance formula will be used to find the lengths of sides

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\

So,

AB = \sqrt{(2-3)^2+(-1-1)^2}\\=\sqrt{(-1)^2+(2)^2}\\=\sqrt{1+4}\\=\sqrt{5}\\=2.24\ unitsBC = \sqrt{(-3-2)^2+(2+1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\= 5.83\ units\\AC = \sqrt{(-3-3)^2+(2-1)^2}\\=\sqrt{(-6)^2+(1)^2}\\=\sqrt{36+1}\\=\sqrt{37}\\=6.08\ units

The perimeter of triangle will be:

P = AB+BC+AC\\= 2.24+5.83+6.08\\=14.15\ units

Hence,

The perimeter of triangle is: 14.15 units

Keywords: Triangle Perimeter

Learn more about perimeter at:

  • brainly.com/question/573729
  • brainly.com/question/572693

#LearnwithBrainly

7 0
3 years ago
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