Ask question

Ask question

All categories

2 years ago

6

Hong purchased n notebooks. They were 5 dollars each. Write an equation to represent the total cost c that Hong paid.

1 answer:

klio [65]2 years ago

4 0

Answer:

5n=c

Step-by-step explanation:

the equation 5n=c can represent the total cost Hong would have paid for the notebooks because given that each notebook costs $5, you would multiply 5 by the number of notebooks (n) that Hong would be purchasing, which would bring you to the cost (c) of the notebooks all together

sorry for the delay. hope this helps

You might be interested in

Sketch and write the equation for each line : y = mx<br> +b

snow_lady [41]

Answer:

equation y =7/4x+1

slope = 7/4

Step-by-step explanation:

We have two points so we can find the slope

m =(y2-y1)/ (x2-x1)

= (4--3)/(2--2)

= (4+3) / (2+2)

= 7/4

We know the slope and the y intercept

We can write the equation using y = mx+b where m is the slope and b is the y intercept

y= 7/4x +1

We put at dot at (0,1) and then go up 7 and to the right 4 . We put another dot

Connect the dots and we have our line.

We could also put dots at (-2,-3) and (2,4) and connect the dots.

7 0

3 years ago

What is the closest estimate for 179 divided by 9

vazorg [7]

179 / 9 is about 20
exact = 19.888888

3 0

3 years ago

Special right triangles

Korolek [52]

Answer:

see down

Step-by-step explanation:

$cos 60 = \frac{x}{6\sqrt{3} } \\x = 6\sqrt{3} * cos60\\x = 6\sqrt{3} * \frac{1}{2} \\x = 3\sqrt{3}$

5 0

3 years ago

Pls show full working out

sweet-ann [11.9K]

Answer:

Question 1a. i) $x=1.8m$

Question 1a. ii) $Volume=27.6m^3$

Question 1b) $Volume=65.9m^3$

Explanation:

<u><em>Question 1 a. i) Find the value of x.</em></u>

$tan(\theta )=\dfrac{opposite\text{ }leg}{adjacent\text{ }leg}$

For the smalll triangle you can write:

$tan(\theta )=\dfrac{x}{1m}$

For tthe big triangle:

$tan(\theta )=\dfrac{x+2.7m}{2.5m}$

Substitute:

$\dfrac{x}{1m}=\dfrac{x+2.7m}{2.5m}$

Solve for x:

$2.5x=x+2.7m\\\\2.5x-x=2.7m\\\\1.5x=2.7m\\\\x=2.7m/1.5\\\\x=1.8m$

<u><em>Question 1a ii) Find the volume of the frustrum</em></u>

Find the volume of a cone with height = 2.7m + 1.8m = 4.5m, and radius = 2.5m

Formula:

$Volume=(1/3)\pi \times radius^2\times height$

Substitute:

$Volume=(1/3)\pi \times (2.5m)^2\times 4.5m=9.375\pi m^3$

Find the volume of a cone with heigth = 1.8m and radius = 1m

$Volume=(1/3)\pi \times (1m)^2\times 1.8m=0.6\pi m^3$

Subtract the volume of the small cone from the volume of the big cone

$Volume\text{ }of\text{ }frustrum=9.375\pi m^3-0.6\pi m^3=8.775\pi m^3\approx 27.6m^3$

<u><em>Question 1b. Calculate the volume of the bin</em></u>

<u>i) Upper frustrum</u>

This is the same frustrum from the equation of above, thus ist volume is 27.6m³.

<u>ii) Lower frustrum</u>

$\dfrac{x}{2.0m}=\dfrac{x+2.4m}{2.5m}$

$2.5x=2(x+2.4m)\\\\2.5x=2x+4.8m\\\\0.5x=4.8m\\\\x=9.6m$

$Volume=(1/3)\pi \times (2.5m)^2\times (9.6m+2.4m)-(2.0m)^2\times (9.6m)$

$Volume=38.3m^3$

<u>iii) Add the volume of the two frustrums</u>

$Volume=27.6m^3+38.3m^3=65.9m^3$

6 0

3 years ago

Timothy is an hourly employee and he can work maximum of 40 hours in a week. If the weekly salary depends on the number of hours

Gennadij [26K]

Answer:

C

Step-by-step explanation:

0 ≤ h ≤ 40, h ∈ R

Hope this helps :)

7 0

2 years ago