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2 years ago

WILL GIVE BRAINLIEST, 5/5 RATING, AND LIKE!!!

Mathematics

1 answer:

atroni [7]2 years ago

8 0

Answer:

230

Step-by-step explanation:

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Quadrant:

NISA [10]

<h2>✒️Area Between Curves</h2>

$\small\begin{array}{ |c|c} \hline \bold{Area\ Between\ Curves} \\ \\ \textsf{Solving for the intersection of }\rm y = x^2 + 2\textsf{ and }\\ \rm y = 4, \\ \\ \qquad \begin{aligned} \rm y_1 &=\rm y_2 \\ \rm x^2 + 2 &=\rm 4 \\ \rm x^2 &= \rm 2 \\ \rm x &=\rm \pm \sqrt{2} \end{aligned} \\ \\ \textsf{We only need the first quadrant area bounded} \\ \textsf{by the given curves so the integral for the area} \\ \textsf{would then be} \\ \\ \boldsymbol{\displaystyle \rm A = \int_{\ a}^{\ b} {\left( \begin{array}{c}\text{upper} \\ \text{function}\end{array} \right) - \left( \begin{array}{c} \text{lower} \\ \text{function} \end{array} \right)\ dx}} \\ \\ \displaystyle \rm A = \int_{0}^{\sqrt{2}} \Big[4 - (x^2 + 2)\Big]\ dx \\ \\ \displaystyle \rm A = \int_{0}^{\sqrt{2}} (2 - x^2)\ dx \\ \\ \rm A = \left[2x - \dfrac{x^3}{3}\right]_{0}^{\sqrt{2}} \\ \\ \rm A = 2\sqrt{2} - \dfrac{\big(\sqrt{2}\big)^3}{3} \\ \\ \rm A = 2\sqrt{2} - \dfrac{2\sqrt{2}}{3} \\ \\\red{\boxed{\begin{array}{c} \rm A = \dfrac{4\sqrt{2}}{3}\textsf{ sq. units} \\ \textsf{or} \\ \rm A \approx 1.8856\textsf{ sq. units} \end{array}}} \\\\\hline\end{array}$

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5 0

2 years ago

L varies directly with the square of Z. L is 12 when Z is 2. Find the value of L when Z is 4.

kow [346]

Answer:

L = 48

Step-by-step explanation:

Given that L varies directly with Z² , then the equation relating them is

L = kZ² ← k is the constant of variation

To find k use the condition L = 12 when Z = 2 , then

12 = k × 2² = 4k ( divide both sides by 4 )

3 = k

L = 3Z² ← equation of variation

When Z = 4 , then

L = 3 × 4² = 3 × 16 = 48

7 0

2 years ago

Simplify each expression.<br> 20-2.32<br> 0 18<br> O 11<br> O 60<br> O 2.

Vladimir [108]

Answer:

the answer for this question is 18

8 0

3 years ago

(SAT Prep) Find the value of x.

mario62 [17]

Answer:

x = 65°

Step-by-step explanation:

Naming the sides of the parallelogram formed ABCD as shown in the attached image to this solution.

Angle A = 2x (vertically opposite angles are equal)

Angle A = Angle C (opposite angles of a parallelogram are equal)

Angle A = Angle C = 2x

(Angle C) + 50° = 180° (Sum of angles on a straight line is 180°)

2x + 50° = 180°

2x = 180° - 50° = 130°

x = (130°/2) = 65°

Hope this Helps!!!

6 0

2 years ago

A support beam to be placed at a 28° angle of elevation so that the top meets a vertical beam 1.6 meters above the horizontal fl

daser333 [38]

1.6/sin(28)
The answer is B

5 0

2 years ago