Question

How do you solve 3x+9y=-7

Answer 1

Solve Equationssolve Sqrt[x - 1] + Sqrt[x + 1] == 2solve e^(2x) - 5e^x + 6 = 0 over the realssolve sin(x) + cos(2x) = 0Algebraevaluate x (2x-1) (2-x) at x = 3what is f(x) = (x^2 e^x)/(x-1) when x = -1Find Interceptsx intercepts of 2 x^3 - 5 x^2 + 4 x - 1y intercepts of 5x^4 -10x^2 + 2x - 2Medianmedian {-5,7,3,5,5,12}

Answer 2

$3x+9y=-7\ \ \ \ \ |subtract\ 3x\ from\ both\ sides\\\\9y=-3x-7\ \ \ \ \ \ |divide\ both\ sides\ by\ 9\\\\\boxed{y=-\frac{1}{3}x-\frac{7}{9}}$