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Volgvan
3 years ago
10

Express 24% as a fraction in lowest term​

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
3 0
24/100 reduced is going to be 6/25. Hope this helps!!
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What is the probability help me ,1.)3/72 2.)3/20,3.)3/10,4.)17/20
cricket20 [7]

Answer:

3/10

Step-by-step explanation:

  1. add 7+4+6+3=20
  2. the take how many times both coins landed on heads which is 6 and put the 6 over 20
  3. then divide by 2 because 2 can go into both 6 and 20
  4. and you end up with 3/10 which you can't simplify any more.
8 0
3 years ago
Inductive and deductive reasoning differ in which way?
Brums [2.3K]

Answer:

(D) Conclusions drawn using deductive reasoning are always valid, while conclusions drawn using inductive reasoning may or may not be valid.

Step-by-step explanation:


7 0
3 years ago
Burnem Inc. manufactures thumb drives and sells them to a distributor. Burnem's total cost and total revenue (in dollars) for x
AlladinOne [14]

Answer:

444 thumb drives

Step-by-step explanation:

Break even is the point at which the proceeds are equal to the costs i.e. when Total cost = Total revenue. So using the equations provided, the breakeven point for Burnem Inc. will be 4x + 4884 = 15x, where x is number of thumb drives. We solve for x to get the answer:

4x + 4884 = 15x

4884 = 15x - 4x

4884 = 11x

x = 4884/11

x = 444 thumb drives

3 0
3 years ago
Please help.
kati45 [8]
-9 < 6 -v < 9 . . . . two inequalities
-15 < -v < 3 . . . . . subtract 6
-3 < v < 15 . . . . . . multiply by -1

6 0
3 years ago
A. Work of 5 Joules is done in stretching a spring from its natural length to 16 cm beyond its natural length. What is the force
kirza4 [7]

Answer:

(a) 62.5 N

(b) 694.4 N/m

(c) 41.7 N

Step-by-step explanation:

Work done in stretching a spring is

W = \frac{1}{2}Fe=\frac{1}{2}ke^2 since F=ke

F is the applied force, E is the elongation and k is the spring constant.

(a) Here, e = 16 cm = 0.16 m

W = \frac{1}{2}Fe

F = \dfrac{2W}{e} = \dfrac{2\times5}{0.16}=62.5\text{ N}

(b) Here, e = 12 cm = 0.12 m

W =\frac{1}{2}ke^2

k=\dfrac{2W}{e^2}=\dfrac{2\times5}{0.12^2}=694.4\text{ N/m}

(c) The restoring force is the same as the applied force.

F = \dfrac{2W}{e} = \dfrac{2\times5}{0.12}=41.7\text{ N}

4 0
4 years ago
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