A) A = 20,000 [Principle] * (0.05 [Interest] * 4 [Number of years]) = $4,000 interest
b) A = 20,000 [Principle] * (0.05 [Interest] * 2 [Number of years]) = $2,000 interest
The answer is 16.
First of all, you need to divide 4 by 1/4.
4/1 / 1/4 = 1.
15 - 1 + 2
Next, you go from left to right with addition and subtraction, so subtract 1 from 15 first.
15 - 1 = 14
14 + 2
Finally, add 14 and 2.
14 + 2 = 16.
The mean and range for class A are 84.4 and 20 while the mean and range for class B are 83.6 and 8. Class B is more consistant then class A.
<h3>How to calculate the mean?</h3>
We can see from the data that the consistency of class B is more becuase the repeatation of the same score is more in class B then class A and the range of class B is also less then the class A.
It should be noted that mean simply means average. It's the addition of the numbers divided by the total numbers.
In this case, the computation will be:
Class A: Mean = 422/5= 84.4.
Range: 94-74 = 20
Class B: Mean = 418/5 = 83.6.
Range= 88-80 = 8
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Well, those 5 extra yards had given her an extra $100, so the yards she cut, plus those she trimmed, had given her $315. To cut one and trim another one she takes $35. This means 9 yards were cut and 14 trimmed. (do a division, 315/35=9).
Answer:
median: 10 <h <13
mean: 12.12
Step-by-step explanation:
