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4 years ago

Please help! For y = 4x 2x^2 - x^3, show how to find the value for y, when x = 2 show your work

1 answer:

6 0

Since x=2, you plug it into your equation by replacing all the x with 2. You would then solve it by following the PEMDAS rule. y= 4(2) + 2(2)^2 - (2)^3 y= 4(2) +2(4) - 8 y= 8 + 8 - 8 y= 16 - 8 y= 8

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3 years ago

Please solve the problem with steps

Debora [2.8K]

Answer:

Infinite series equals 4/5

Step-by-step explanation:

Notice that the series can be written as a combination of two geometric series, that can be found independently:

$\frac{3^{n-1}-1}{6^{n-1}} =\frac{3^{n-1}}{6^{n-1}} -\frac{1}{6^{n-1}} =(\frac{1}{2})^{n-1} -\frac{1}{6^{n-1}}$

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The second one: $\frac{1}{6^{n-1}}$ is a geometric sequence of first term "1", and common ratio (r) " $\frac{1}{6}$ ". Again, since the common ratio is smaller than one, we can find its infinite sum:

$Infinite\,Sum=\frac{a_1}{1-r} = \frac{1}{1-\frac{1}{6} } =\frac{1}{\frac{5}{6} } =\frac{6}{5}$

now we simply combine the results making sure we do the indicated difference: Infinite total sum= $2-\frac{6}{5} =\frac{10-6}{5} =\frac{4}{5}$

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Harlamova29_29 [7]

Write it as a mixed fraction 7/5 = 1 2/5

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4 years ago