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Fittoniya [83]
2 years ago
7

In the given figure, O is centre of the circle. Find the value of x and y? ​

Mathematics
2 answers:
timurjin [86]2 years ago
5 0

Answer:

  • The value of x=30cm and y = 18cm.

Step-by-step explanation:

P is the exterior point to the circle with centre O

Radius = 5cm

Length of the tangent = 12 cm

Distance between the point and centre of the circle = x cm

We know that

The angle between the radius of the circle and the tangent at the point of contact is 90°

By Pythagoras Theorem

Hypotenuse² = Side²+Side²

⇛OP² = OT1² +PT1²

⇛x² = 24²+18²

⇛x² = 576+324

⇛x² = 900

⇛x² = 30²

⇛x = √(30)²

⇛x = √(30*30)

<h3>⇛x = 30cm</h3>

We know that

The lengths of tangents drawn from the exterior point to the circle are equal.

PT1 = PT2

<h3>y = 18 cm</h3>

<u>Answer</u>: Hence, the value of x=30cm and y = 18cm.

<u>also</u><u> read</u><u> similar</u><u> questions</u><u>:</u> In the given figure, O is centre of the circle. Find the⁠…

brainly.com/question/26230013?referrer

jok3333 [9.3K]2 years ago
4 0

Answer:

x=30 cm

y=24 cm

Step-by-step explanation:

y=24 cm

x=√(24²+18²)=√[6²(4²+3²)]=6√(16+9)=6√25=6×5=30 cm

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Answer:

  1. x - 5y = -5; x -5y = 35
  2. there are no solutions, the lines are parallel so do not intersect

Step-by-step explanation:

<h3>1.</h3>

We judge the x-intercept to be about 5 times as far from the origin as the y-intercept is. If we take the y-intercept of the blue line to be +1, then the equation of that line can be x -5y = -5. The y-intercept of the black line appears to be about 7 times as far from the origin as for the blue line, so the constant will be multiplied by -7: x -5y = 35.

The two equations in the system of equations could be ...

  • x -5y = -5
  • x -5y = 35

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<h3>2.</h3>

We have assumed the two lines are parallel, so they will not intersect. A point of intersection would be a solution to the system. The system of equations will have no solutions.

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2 years ago
Amy purchased a brand-new mountain bike, which she's riding through
Neko [114]

Answer:

The Acceleration of bike after 3 minutes of ride is  14 meter² per minutes

Step-by-step explanation:

Given as :

The displacement of bike is the function of time

i.e s(t) = t³ - 2 t² + 3  meters

The Time of bike acceleration = t = 3 minutes

Let The Acceleration of bike = a meter² per minutes

Now, According to question

∵ <u>Acceleration is define as the rate of change of velocity</u>

i.e acceleration = \dfrac{\textrm velocity}{\textrm time}

or, a =  \dfrac{\textrm v}{\textrm t}

And

<u>Velocity is define as rate of change of displacement</u>

i.e velocity =  \dfrac{\textrm displacement}{\textrm time}

Or, v =  \dfrac{\textrm s}{\textrm t}

Since here displacement is function of time

So , v = \frac{\partial s(t)}{\partial t}

Or, v =   \frac{\partial (t³ - 2 t² + 3)}{\partial t}

Or, v = 3 t² - 4 t + 3

So, velocity is the function of time = v = 3 t² - 4 t + 3   meter per minutes

Now, Again

Acceleration = a = \frac{\partial v}{\partial t}

Or, a = \frac{\partial (3 t² - 4 t + 3)}{\partial t}

Or, a = 6 t - 4

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Now, Acceleration of bike after 3 minutes

So, at t = 3 min

i.e a = 6 t - 4

Or, a = 6 × 3 - 4

Or, a = 18 - 4

∴  a = 14 meter² per minutes

Hence, The Acceleration of bike after 3 minutes of ride is  14 meter² per minutes . Answer

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