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3 years ago

Write each fraction or mixed number as a decimal. 19/25 311/500 5/8 145/8

Mathematics

2 answers:

DanielleElmas [232]3 years ago

5 0

Answer:

19/25 = 0.76

311/500 = 0.622

5/8 = 0.625

145/8 = 18.12500

Step-by-step explanation:

Divide the first number by the second like 145 divided by 18.

Arada [10]3 years ago

5 0

Answer:

19|25 = .76

311|500= .622

5|8= .625

145|8=18.125

Step-by-step explanation:

over here to get a decimal u just have to divide the top number by the bottom number. to get a percent u just have to divide the top by bottom and then multiply by 100

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Mark is solving the equation 4x2 + 2x = -9 using the quadratic formula.

Masteriza [31]

4x^2 + 2x = -9
4x^2 + 2x + 9 = 0

remember that the form of quadratic is ax^2 + bx + c = 0

so
a = 4
b = 2
c = 9

6 0

3 years ago

Which of the following points would be on the graph of the equation y=4x+6

o-na [289]

Some of the possible points using this equation are...
(2,14)
(1,10)
(0,6)
(-1,2)
(-2,-2)

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3 years ago

PLEASE HELP NOW --- >N is a 2-digit even number. If the last two digits of N^2 is the same as N, what is the sum of digits of

taurus [48]

Answer:

76.

Step-by-step explanation:

It is given that N is a 2-digit number.

Last two digits of N^2 is the same as N.

We know that, a number is even if it ends with 0,2,4,6,8.

$2^2=4,4^2=16,6^2=36,8^2=64$

If 0 is in end then we get two zeros in the square of that number.

It is clear that, number should ends with 6 to get the same number at the end.

$16^2=256$

$26^2=676$

$36^2=1296$

$46^2=2116$

$56^2=3136$

$66^2=4356$

$76^2=5776$

$86^2=7396$

$96^2=9216$

It is clear that last two digits of (76)^2 is the same as 76.

Therefore, the required number is 76.

6 0

3 years ago

《MATHEMATICS》

Law Incorporation [45]

<h2>Hey,there..</h2>

${3}^{2} - {2}^{2} \\ (3 + 2) \times (3 - 2) \\ 5 - 1 \\ = 4$

$2) \frac{1}{2} + \frac{2}{3} \\$

$\frac{3+2}{6} \\$

$\frac{5}{6}$

<h2>Hope it helps...</h2>

5 0

3 years ago

Read 2 more answers

Resolve into partial fractions 7-5x/2x^2+x-1

Flauer [41]

The decomposition of partial fractions is to start with the simplified reply and then take it apart, to "decompose" the final expression into its initial polynomial fractions.

Given:

$\to \bold{\frac{7-5x}{2x^2+x-1}}\\\\$

To find:

partial fractions=?

Solution:

$\to \bold{\frac{7-5x}{2x^2+x-1}}\\\\\to \bold{\frac{7-5x}{2x^2+x(2-1)-1}}\\\\\to \bold{\frac{7-5x}{2x^2+2x-x-1}}\\\\\to \bold{\frac{7-5x}{2x(x+1)-1(x+1)}}\\\\\to \bold{\frac{7-5x}{(2x-1)(x+1)} = \frac{A}{(2x-1)} - \frac{B}{(x+1)} }\\\\\to \bold{7-5x = \frac{A ((2x-1)(x+1))}{(2x-1)} - \frac{B((2x-1)(x+1))}{(x+1)} }\\\\\to \bold{7-5x = A(x+1) -B(2x-1) }\\\\$

putting $x=-1$

$\to \bold{7-5(-1) = A(-1+1) -B(2(-1)-1) }\\\\\to \bold{7+5 = A(0) -B(-2-1) }\\\\\to \bold{12 = +3B }\\\\\to \bold{B = \frac{12}{3} }\\\\\to \bold{B = 4 }\\\\$

putting $x= \frac{1}{2}$

$\to \bold{7-5(\frac{1}{2}) = A(\frac{1}{2}+1) -B(2(\frac{1}{2})-1) }\\\\\to \bold{7-\frac{5}{2} = A(\frac{3}{2}) -B((\frac{2}{2})-1) }\\\\\to \bold{7-\frac{5}{2} = A(\frac{3}{2}) -B(1-1) }\\\\\to \bold{\frac{14-5}{2} = A(\frac{3}{2}) -B(0) }\\\\\to \bold{\frac{9}{2} = A(\frac{3}{2})}\\\\\to \bold{\frac{9}{2} \times \frac{2}{3} = A}\\\\\to \bold{\frac{9}{3} = A}\\\\\to \bold{A=3}\\\\$

So, the final answer is " $\bold{\frac{7-5x}{(2x-1)(x+1)} = \frac{3}{(2x-1)} - \frac{4}{(x+1)} }\\\\$ ".

Learn more:

brainly.com/question/22286068

3 0

3 years ago