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2 years ago

2) Eduardo put some money into an account 15 years ago that paid 6% interest compounded

1 answer:

7 0

Answer:but you count the exact number of days you have held the money in computing the interest. To use ... The interest I earn on the account is the interest the bank pays ... account earns 7.5% interest, compounded yearly, and no further deposits or withdraws are ... 1, 2001 was 2 years interest on $575, plus the $1,500 deposit:.

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Three pounds of shrimp costs 16.47 at the grocery store. ? is the unit price of the shrimp in dollars per pound

Diano4ka-milaya [45]

the answer is $5.49. hope that helps

6 0

3 years ago

3. Two cars are parked, 150m apart, and on opposite sides of a building. A camera on the top of the building rotates and can vie

allsm [11]

Answer:

<em>The building is 61.5 m tall</em>

Step-by-step explanation:

The image below is a diagram where all the given distances and angles are shown. We have additionally added some variables:

h = height of the building

a, b = internal angles of each triangle

x = base of each triangle

The angles a and b can be easily found by subtracting the given angles from 90° since they are complementary angles, thus:

a = 90° - 37° = 53°

b = 90° - 42° = 48°

Now we apply the tangent ratio on both triangles separately:

$\displaystyle \tan a=\frac{\text{opposite leg}}{\text{adjacent leg}}$

$\displaystyle \tan 53^\circ=\frac{150-x}{h}$

$\displaystyle \tan 48^\circ=\frac{x}{h}$

From the last equation:

$x=h.\tan 48^\circ$

Substituting into the first equation:

$\displaystyle \tan 53^\circ=\frac{150-h.\tan 48^\circ}{h}$

Operating on the right side:

$\displaystyle \tan 53^\circ=\frac{150}{h}-\tan 48^\circ$

Rearranging:

$\displaystyle \tan 53^\circ+\tan 48^\circ=\frac{150}{h}$

Solving for h:

$\displaystyle h=\frac{150}{\tan 53^\circ+\tan 48^\circ}$

Calculating:

h = 61.5 m

The building is 61.5 m tall

5 0

3 years ago

sergey [27]

Answer:

His money earned $36 after 3 months

Step-by-step explanation:

* Lets revise the rules of simple interest

- Simple Interest Equation (Principal + Interest)

A = P(1 + rt)

- Where:

• A = Total amount (principal + interest) future amount

• P = Principal Amount

• I = Interest Amount

• r = Rate of Interest per year in decimal; r = R/100

• t = Time Period involved

* To calculate the interest I use the formula

I = P × r × t

* Lets solve the problem

- The rate is annual

- The interest calculated after 3 months

∴ I = P × R/100 × t/12

∵ P = $3600.00

∵ R = 4%

∵ t = 3 month

∴ I = 3600.00 × 4/100 × 3/12 = $36

* His money earned $36 after 3 months

5 0

3 years ago

Please help? Thank you

Alex17521 [72]

Answer:

I hope the answer is correct

4 0

2 years ago

ln(y+1)-lny=1+3lnx . Express y in terms of x, in a form not involving logarithms. (4 marks, Maths CIE A level)

Delicious77 [7]

$remember$
$ln(x)=log_e(x)$
$and$
$log_x(a)-log_x(b)= log_x( \frac{a}{b} )$
$and$
$log_a(b)=c$ means $a^c=b$
$and$
$blog(a)=log(a^b)$

$so$

$ln(y+1)-ln(y)=1+3ln(x)$
$ln( \frac{y+1}{y} )=1+ln(x^3)$

$minus$ $ln(x^3)$ $from$ $both$ $sides$

$ln( \frac{y+1}{y}-ln(x^3) )=1$
$ln( \frac{y+1}{yx^3})=1$
$log_e( \frac{y+1}{yx^3})=1$

$translate$

$e^1=\frac{y+1}{yx^3}$
$e=\frac{y+1}{yx^3}$

$times$ $both$ $sides$ $by$ $yx^3$

$eyx^3=y+1$

$minus$ $y$ $from$ $both$ $sides$

$eyx^3-y=1$
$y(ex^3-1)=1$

$divide$ $both$ $sides$ $by$ $(ex³-1)$

$y= \frac{1}{ex^3-1}$

6 0

2 years ago

Read 2 more answers