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3 years ago

8

Marsia will make a frame for her picture the length of the picture is 15 inches the width is 1/3 of the length how much wood doe

s Marsia need for the frame

1 answer:

marysya [2.9K]3 years ago

6 0

She needs 40 inches total. Hope it helps!

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PLEASE HELP ASAP 9TH GRADE MATH AND I NEED HELP, 15 POINTS AND BRAINLIST HELPPPP

Sunny_sXe [5.5K]

Answer:

x = 40°

Step-by-step explanation:

Given that ∠SRT ≅ ∠STR

Then ∠STR = 20

∠STR and ∠STU are what you call supplementary angles. This means that the sum of their measurements is equal to 180° because they form a straight line.

So if:

∠STR + ∠STU = 180°

m∠STU = 4x

m∠STR = 20

Then:

4x + 20° = 180°

Now we solve for x:

$4x + 20 = 180\\\\Subtract\;20\;from\;both\;sides\;of\;the\;equation\\\\4x + 20 - 20 = 180 - 20\\4x = 160\\\\Divide\;both\;sides\;of\;the\;equation\;by\;4\\\\\dfrac{4x}{4}=\dfrac{160}{4}\\\\x = 40$

x = 40°

8 0

3 years ago

Hell help me out thank youuuuuu byeee

Crank

Answer:

if im right its number 4!! if its not right sorry i did the math and thats what i got!!

4 0

3 years ago

Simplify (a+b)(a^2-ab+b^2)

Pani-rosa [81]

Answer: a^3 - b^3

Step-by-step explanation:

6 0

3 years ago

What is the solution of -8/2y-8=5/y+4 - 7y+8/y^2-16

blsea [12.9K]

Answer:

<h2>y = 8</h2>

Step-by-step explanation:

$Domain:\\\\2y-8\neq0\ \wedge\ y+4\neq0\ \wedge\ y^2-16\neq0\\\\2y\neq8\ \wedge\ y\neq-4\ \wedge\ y^2\neq16\\\\y\neq4\ \wedge\ y\neq-4\ \wedge\ y\neq\pm\sqrt{16}\\\\y\neq4\ \wedge\ y\neq-4\ \wedge\ y\neq-4\ \wedge\ y\neq4\\\\\boxed{y\neq-4\ \wedge\ y\neq4}\\\\===========================$

$\dfrac{-8}{2y-8}=\dfrac{5}{y+4}-\dfrac{7y+8}{y^2-16}\\\\\dfrac{-8}{2(y-4)}=\dfrac{5}{y+4}-\dfrac{7y+8}{y^2-4^2}\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\\\\dfrac{-8}{2(y-4)}=\dfrac{5}{y+4}-\dfrac{7y+8}{(y-4)(y+4)}\qquad\text{multiply both sides by (-2)}\\\\\dfrac{8}{y-4}=-\dfrac{10}{y+4}+\dfrac{14y+16}{(y-4)(y+4)}\qquad\text{add}\ \dfrac{10}{y+4}\ \text{to both sides}\\\\\dfrac{8}{y-4}+\dfrac{10}{y+4}=\dfrac{14y+16}{(y-4)(y+4)}$

$\dfrac{8(y+4)}{(y-4)(y+4)}+\dfrac{10(y-4)}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\\\\\dfrac{8(y+4)+10(y-4)}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\qquad\text{use the distributive property}\\\\\dfrac{8y+32+10y-40}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\qquad\text{combine like terms}\\\\\dfrac{(8y+10y)+(32-40)}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\\\\\dfrac{18y-8}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\iff18y-8=14y+16\\\\18y-8=14y+16\qquad\text{subtract 14y from both sides}$

$4y-8=16\qquad\text{add 8 to both sides}\\\\4y=24\qquad\text{divide both sides by 4}\\\\y=8\in D$

8 0

3 years ago

Anyone know which one is the right one

sergiy2304 [10]

1) the square root of 64=8

2) The square root of a^4=a^2

3) b^5=b√b

so the first amount simplifies to 8a²b²√b

4) ∛64=4, as 4×4×4=64

5) ∛a^5=a√a²

6)∛b^4=b√b

so...the second amount is equal to 4ab∛a²b

The last one should be correct

Hope this helped :)

6 0

3 years ago