Answer:
a) Sample space (S) = {TR, TL, Cs}
b) Pr(Vehicle Turns) = 2/3.
Step-by-step explanation:
a) By sample space (S) we mean the list all possible outcome of an event. From the illustration in the question, only three (3) outcome is possible:
i) Vehicle Turn Right (TR)
ii) Vehicle Turn Left (TL)
iii) Continue Straight ahead (Cs)
And since the experiment consists of observing the movement of a single vehicle through the intersection, then, the sample space (S) is:
==> {TR, TL, Cs}
b) Since we are assuming that all sample points are equally likely, it imply that they have equal probability of occurring. And by probability:
Pr(TR) = 1/3
Pr(TL) = 1/3
Pr(Cs) = 1/3
Meanwhile, the question wants us to find the probability that the vehicle turns. This means, the vehicle turning either right or left. Thus;
Pr(vehicle turns) = Pr(TR) or Pr(TL) = Pr(TR) + Pr(TL)
Pr(vehicle turns) = (1/3) + (1/3) = 2/3
since it is exactly in the halfway between 