Answer:
The percentile rank for Park Street's revenues this week is 60th.
The percentile rank for Bridge Road's revenues this week is 73rd.
Step-by-step explanation:
The missing information are as follows:
Variable N Mean SD
Park 36 6611 3580
Bridge 40 5989 1794
A z-score (aka, a standard score) specifies the number of standard deviations an observation is from the mean.
The formula to compute the z-score is,
, where X = observation, µ = mean, σ = standard deviation.
Compute the <em>z</em>-score for Park Street's revenues, $7500 as follows:
![Z_{p} = \frac{(X - \mu)}{\sigma}=\frac{7500-6611}{3580}=0.25](https://tex.z-dn.net/?f=Z_%7Bp%7D%20%3D%20%5Cfrac%7B%28X%20-%20%5Cmu%29%7D%7B%5Csigma%7D%3D%5Cfrac%7B7500-6611%7D%7B3580%7D%3D0.25)
The <em>z</em>-score for Park Street's revenues this week is 0.25.
Compute the percentile rank for Park Street's revenues this week as follows:
![P(Z](https://tex.z-dn.net/?f=P%28Z%3CZ_%7Bp%7D%29%3DP%28Z%3C0.25%29%3D0.5987%5Capprox%200.60%5C%20%5Ctext%7Bor%7D%5C%2060%5C%25)
The percentile rank for Park Street's revenues this week is 60th.
This implies that the Park Street's performed better than 60% of the revenue recorded for the restaurant.
Compute the <em>z</em>-score for Bridge Road's revenues, $7100 as follows:
![Z_{p} = \frac{(X - \mu)}{\sigma}=\frac{7100-5989}{1794}=0.62](https://tex.z-dn.net/?f=Z_%7Bp%7D%20%3D%20%5Cfrac%7B%28X%20-%20%5Cmu%29%7D%7B%5Csigma%7D%3D%5Cfrac%7B7100-5989%7D%7B1794%7D%3D0.62)
The <em>z</em>-score for Bridge Road's revenues this week is 0.62.
Compute the percentile rank for Bridge Road's revenues this week as follows:
![P(Z](https://tex.z-dn.net/?f=P%28Z%3CZ_%7Bb%7D%29%3DP%28Z%3C0.62%29%3D0.7324%5Capprox%200.73%5C%20%5Ctext%7Bor%7D%5C%2073%5C%25)
The percentile rank for Bridge Road's revenues this week is 73rd.
This implies that the Bridge Road's performed better than 73% of the revenue recorded for the restaurant.