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Leya [2.2K]
3 years ago
13

) Explain two ways you could solve 20 = 5(-3 + x)​

Mathematics
1 answer:
inn [45]3 years ago
7 0

Answer:

You can distribute the 5 into the parentheses, or u can divide on both sides to get rid of the 5. Either way, you're going to get the same answer.

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Laws Of Indicies<br>Can someone please help me with this?​
nasty-shy [4]

Answer:

See below

Step-by-step explanation:

1) :  {a}^{5}  {b}^{4}  {c}^{3}  \div  {a}^{2}  {b}^{3} c \\  \\  = {a}^{5 - 2}  {b}^{4 - 3}  {c}^{3 - 1}  \\  \\  = {a}^{3}  {b}^{1}  {c}^{2}  \\  \\ = {a}^{3}  {b}  {c}^{2}  \\  \\  \\2)\:  (x^2 y^3)^3\\\\= x^{2\times 3}y^{3\times 3}\\\|= x^{6}y^{9}\\\\\\3)\:5 {a}^{4}   \div ( {a}^{2}  \times 3a) \\  \\  = 5 {a}^{4}   \div (3 {a}^{2 + 1}  ) \\  \\  = 5 {a}^{4}   \div (3 {a}^{3}  ) \\  \\  =   \frac{5}{3}  {a}^{4 - 3}  \\  \\ =   \frac{5}{3}  {a} \\  \\  \\ 4)\: \frac{14 {a}^{5} }{2 {a}^{3} \times 7 {a}^{4}  }  \\  \\  =   \frac{14 {a}^{5} }{2 \times 7 {a}^{3 + 4} }   \\  \\  =   \frac{ \cancel{14} {a}^{5} }{ \cancel{14}{a}^{3 + 4} }    \\  \\  =   \frac{  {a}^{5} }{ {a}^{7} }   \\  \\  =  {a}^{5 - 7}  \\  \\  =  {a}^{ - 2}  \\  \\  =  \frac{1}{{a}^{2} }  \\  \\

8 0
3 years ago
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Where is the picture mf?
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2 years ago
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Answer:

the answer is point G

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