Ask question

Ask question

All categories

4 years ago

6

An alloy composed of nickel, zinc, and copper in a 4:1:2 ratio. How many kilograms of each metal are needed to make 35 kg of thi

s alloy?

2 answers:

9966 [12]4 years ago

8 0

Answer:

Let X be the amount of each metal needed to make 35 Kg of this alloy.

We know that an alloy is composed of nickel, zinc and copper in a proportion

4:1:2. Therefore, we have:

$4X+1X+2X = 35$

$7X = 35$

$X=\frac{35}{7}$

$X=5$ Kg

Therefore, there are $5 \times 4 =20$ kg of nickel, $1 \times 5 =5$ kg of zinc, and $2 \times 5 = 10$ kg of copper needed to make 35 kg of this alloy

gregori [183]4 years ago

7 0

Answer:

Step-by-step explanation:

The ration of weight of nickel, zinc, and copper in an alloy is 4:1:2

The weight of alloy can be written as

4x + x + 2x = 35 Kg

7 x = 35 Kg

X = 35 Kg/7

X = 5kg

The weight of nickel the alloy = 4 x 5 = 20 Kg

The weight of zinc in the alloy= 1 x 5 = 5kg

The weight of copper in the alloy = 2 x 5 = 10 kg

You might be interested in

Help plsssssssssssss

jonny [76]

Answer:

144

Step-by-step explanation:

72% of 200 is 144

Equation: 0.72*200 = 144

7 0

3 years ago

Read 2 more answers

What is always true about a line that slants downward from left to right?

Maslowich

Answer:

A

Step-by-step explanation:

Image result for what is always true about a line that slants downward from left to right

A line that slants down from left to right has a negative slope. Horizontal and vertical lines also have a slope. A horizontal line has a change in x, but it does not have a change in y. The slope of a horizontal line is 0.

4 0

3 years ago

Read 2 more answers

Angle θ is in standard position. If (8, -15) is on the terminal ray of angle θ, find the values of the trigonometric functions.

notsponge [240]

ANSWER

$\sin( \theta) = - \frac{15}{17}$

$\csc( \theta) = - \frac{17}{15}$

$\cos( \theta) = \frac{8}{17}$

$\sec( \theta) = \frac{17}{8}$

$\tan( \theta) = - \frac{15}{8}$

$\cot( \theta) = - \frac{8}{15}$

EXPLANATION

From the Pythagoras Theorem, the hypotenuse can be found.

${h}^{2} = 1 {5}^{2} + {8}^{2}$

${h}^{2} = 289$

$h = \sqrt{289}$

$h = 17$

The sine ratio is negative in the fourth quadrant.

$\sin( \theta) = - \frac{opposite}{hypotenuse}$

$\sin( \theta) = - \frac{15}{17}$

The cosecant ratio is the reciprocal of the sine ratio.

$\csc( \theta) = - \frac{17}{15}$

The cosine ratio is positive in the fourth quadrant.

$\cos( \theta) = \frac{adjacent}{hypotenuse}$

$\cos( \theta) = \frac{8}{17}$

The secant ratio is the reciprocal of the cosine ratio.

$\sec( \theta) = \frac{17}{8}$

The tangent ratio is negative in the fourth quadrant.

$\tan( \theta) = - \frac{opposite}{adjacent}$

$\tan( \theta) = - \frac{15}{8}$

The reciprocal of the tangent ratio is the cotangent ratio

$\cot( \theta) = - \frac{8}{15}$

8 0

3 years ago

Read 2 more answers

I need answer immediately!!!!!!

Anon25 [30]

Answer:

y = -2/3x - 5

Step-by-step explanation:

5 0

3 years ago

What is the area of the sector of the circle below, if the radius is 5 m. and the central angle < AOB measures 88 °. (round a

MariettaO [177]

Answer:

b 19.2

Step-by-step explanation:

a = $\pi$ $r^{2}$ for a circle. We do not want to find the area for a whole circle. We only want to find the area for part of a circle. a hole circle is 360 degrees.

a = $\frac{88}{360}$ $\pi$ $r^{2}$

a = $\frac{88}{360}$ $\pi$ ( $5^{2}$ )

a = 19.2 rounded.

8 0

2 years ago

Read 2 more answers