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Olenka [21]
2 years ago
13

Write a polynomial in standard form that meets the following conditions. Assume a=1 and your function is f(x), The zeros are 5 a

nd -4
Mathematics
1 answer:
jeka57 [31]2 years ago
7 0

Polynomials are equations that uses variables and several terms

The polynomial in standard form is f(x) = x^2 - x -20

<h3>How to determine the polynomial</h3>

The polynomial has 2 zeros.

So, the form of the polynomial is:

f(x) = a(x - x1)(x - x2)

The zeros of the polynomial are 5 and -4.

So, the equation becomes

f(x) = a(x - 5)(x + 4)

The value of a = 1.

So, we have;

f(x) = 1(x - 5)(x + 4)

This gives

f(x) = (x - 5)(x + 4)

Expand

f(x) = x^2 - x -20

Hence, the polynomial in standard form is f(x) = x^2 - x -20

Read more about polynomials at:

brainly.com/question/2833285

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3 years ago
What are the intercepts of x^2+y-9=0
Dmitry_Shevchenko [17]

Answer:

Zeros

x = -3   point (-3 ,0)

x = 3   point (3 ,0)

Step-by-step explanation:

Using a graphing calculator, we can easily check the intercepts of the equation

y  = -x^2 +9

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3 years ago
−2 1/6 divided by 1 1/4<br> 100 points
galina1969 [7]

Answer:

  • -1 11/15

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<u>−2 1/6 divided by 1 1/4:</u>

  • -2 1/6 ÷ 1 1/4 =
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8 0
3 years ago
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Plz help will mark brainliest if correct answer only ​
statuscvo [17]

Answer:

9. is 3

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Step-by-step explanation:

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7 0
2 years ago
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What number must be added to the expression below to complete the<br> square?<br> x² - 18x
kiruha [24]

Answer:

\boxed {\boxed {\sf 81}}

Step-by-step explanation:

The standard form of a quadratic is:

ax^2+bx+c

To complete the square, the a (leading coefficient) must be 1 and there can only be terms with variables on one side.

The expression given:

x^2-18x

follows these rules. Next, we divide the b (linear coefficient) by 2, then square it. Basically:

(\frac{b}{2})^2

The b in the expression is -18.

(\frac{-18}{2})^2

(-9)^2= -9*-9= 81

This is the number that is added.

5 0
3 years ago
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