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Drupady [299]
2 years ago
13

Solve for x. Write your answer as “x=__” Don’t put the 8 into equation

Mathematics
1 answer:
kifflom [539]2 years ago
3 0

Answer: x=45

Step-by-step explanation:

2x+6=96

2x=90

x=45

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bulgar [2K]
The 6 at the end is the remainder

8 0
3 years ago
Help me please everyone;-;
Debora [2.8K]

Answer:

x - 4

Step-by-step explanation:

\sf \bigg( \dfrac{ {x}^{4} }{ {x}^{3} }  \bigg) - 4

\sf \bull \dfrac{{a}^{m} }{ {a}^{n} }  =  {a}^{m - n}

\sf \:  {x}^{4 - 3}  - 4

\sf{x}^{1}  - 4

\sf \: x - 4

4 0
2 years ago
Read 2 more answers
Give the equation of a line that goes through the point ( − 21 , 2 ) and is perpendicular to the line 7 x − 4 y = − 12 . Give yo
nlexa [21]

Given:

Equation of line 7x-4y=-12.

To find:

The equation of line  that goes through the point ( − 21 , 2 ) and is perpendicular to the given line.

Solution:

The given equation of line can be written as

7x-4y+12=0

Slope of line is

\text{Slope}=-\dfrac{\text{Coefficient of x}}{\text{Coefficient of y}}

m_1=-\dfrac{7}{(-4)}

m_1=\dfrac{7}{4}

Product of slopes of two perpendicular lines is -1. So, slope of perpendicular line is

m_1m_2=-1

m_2=-\dfrac{1}{m_1}

m_2=-\dfrac{4}{7}           [\because m_1=\dfrac{7}{4}]

Now, the slope of perpendicular line is m_2=\dfrac{4}{7} and it goes through (-21,2). So, the equation of line is

y-y_1=m_2(x-x_1)

y-2=-\dfrac{4}{7}(x-(-21))

y-2=-\dfrac{4}{7}x-\dfrac{4}{7}(21)

y-2=-\dfrac{4}{7}x-12

y=-\dfrac{4}{7}x-12+2

y=-\dfrac{4}{7}x-10

Therefore, the required equation in slope intercept form is y=-\dfrac{4}{7}x-10.

7 0
3 years ago
Asap please !
nevsk [136]

Answer:

Maybe, since it's a fair game.

Step-by-step explanation:

8 0
2 years ago
Ryder Industries is considering a project that will produce cash inflows of $92,000 a year for five years. What is the internal
RSB [31]

Answer:

20.02%

Step-by-step explanation:

Formula : NVP = 0 =-P_0 + \frac{P_1}{(1+IRR)} + \frac{P_2}{(1+IRR)^2} + . . . +\frac{P_n}{(1+IRR)^n}

P_0 = 275000

n = 1,2,3,4,5

Substitute the values in the formula :

0 =-275000 + \frac{92000}{(1+IRR)} + \frac{92000}{(1+IRR)^2} + \frac{92000}{(1+IRR)^3}+\frac{92000}{(1+IRR)^4}+\frac{92000}{(1+IRR)^5}

275000 = \frac{92000}{(1+IRR)} + \frac{92000}{(1+IRR)^2} + \frac{92000}{(1+IRR)^3}+\frac{92000}{(1+IRR)^4}+\frac{92000}{(1+IRR)^5}

Solving for IRR using calculator

IRR = 20.02

Hence the internal rate of return if the initial cost of the project is $275,000 is 20.02%

4 0
3 years ago
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