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emmainna [20.7K]

3 years ago

6

How do you simplify 8 to the -2 power

1 answer:

Tems11 [23]3 years ago

3 0

IF you have a scientific calculator that would REALLY be handy here but if you don't then um.... I have no clue what to tell you. Sorry!!

The answer to 8 raised to the -2 power is .015625
Most likely you should round it out so it would be .016

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Find the interquartile range (IQR) for the following data set:

german

The interquartile range is 5!

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8 0

3 years ago

Solve the following differential equation: y" + y' = 8x^2

PtichkaEL [24]

Answer:

$y=y_p+y_h = \frac{8}{3}x^3-8x^2+16x+ C_1 + C_2e^{-x}$

Step-by-step explanation:

Let's find a particular solution. We need a function of the form $y= ax^3+bx^2+cx+d$ such that

$y'= 3ax^2+2bx+c$ and

$y''= 6ax+2b$

$y'+y''= 3ax^2+2bx+c+6ax+2b = 3ax^2+x(2b+6a)+(c+2b) = 8x^2$

then, 3a= 8, 2b+6a =0 and c+2b = 0. With the first equation we obtain

a = 8/3 and replacing in the second equation 2b+6(8/3) = 2b + 16 = 0. Then, b = -8. Finally, c = -2(-8) = 16.

So, our particular solution is $y_p= \frac{8}{3}x^3-8x^2+16x$ .

Now, let's find the solution $y_p$ of the homogeneus equation $y''+y'=0$ with the method of constants coefficients. Let $y=e^{\lambda x}$

$y'=\lambda e^{\lambda x}$

$y''=\lambda^2e^{\lambda x}$

then $\lambda e^{\lambda x}+\lambda^2 e^{\lambda x} = 0$

$e^{\lambda x}(\lambda +\lambda^2)= 0$

$(\lambda +\lambda^2)= 0$

$\lambda (1+\lambda)= 0$

$\lambda =0$ and $\lambda)= -1$ .

So, $y_h = C_1 + C_2e^{-x}$ and the solution is

$y=y_p+y_h =\frac{8}{3}x^3-8x^2+16x+ C_1 + C_2e^{-x}$ .

5 0

3 years ago

40% of the voters vote for Jimmy B. Political for president. 80 million people voted. How many votes did Jimmy get??

antiseptic1488 [7]

Step-by-step explanation:

80,000,000x .4 = 32 million.

4 0

3 years ago

Read 2 more answers

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MA_775_DIABLO [31]

5:6?
Is this it I’m not sure

3 0

3 years ago

PLEASE HELP<br><br> Write the number in standard form.<br><br> (8 × 10) + (1 × 110) + (6 × 11,000)

mote1985 [20]

66,190 is the Answer if you add 80 to 110 and then add 190 to 66000

7 0

3 years ago