Hello from MrBillDoesMath!
Answer:
1/ 91.4
Discussion:
Evaluate 1/ ( 3x^3 + 5.2y) when x = 3, y = 2.
1/ (3 (3)^3 + 5.2(2)) =
1/ ( 3 * 27 + 10.4) =
1/ ( 81 + 10.4) =
1/ (91.4) =
.0109 (approx)
Thank you,
MrB
Use the Pythagorean theorem to find z:
z = √(6^2 + 9^2)
z= √(36 + 81)
z = √117
z = 3√13 = 10.8
Use leg rule to find x:
x/6 = 6/9
Cross multiply:
9x = 36
Divide both sides by 9:
x = 36/9
x = 4
Use Pythagorean theorem to find y:
y = √(6^2 + 4^2)
y= √(36 + 16)
y = √52
y = 2√13 = 7.2
21 420 69 thank you very much
