What is the value of the 5 in 0.750

Tiffany is monitoring the decay of two radioactive compounds in test tubes at her lab. Compound A is continuously decaying at a

trapecia [35]

Answer:

30e-0.12t

40e-0.18t

Step-by-step explanation:

6 0

4 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

s2008m [1.1K]

Answer: 912

===================================

Work Shown:

The starting term is a1 = 3. The common difference is d = 5 (since we add 5 to each term to get the next term). The nth term formula is

an = a1+d(n-1)

an = 3+5(n-1)

an = 3+5n-5

an = 5n-2

Plug n = 19 into the formula to find the 19th term

an = 5n-2

a19 = 5*19-2

a19 = 95-2

a19 = 93

Add the first and nineteenth terms (a1 = 3 and a19 = 93) to get a1+a19 = 3+93 = 96

Multiply this by n/2 = 19/2 = 9.5 to get the final answer

96*9.5 = 912

I used the formula

Sn = (n/2)*(a1 + an)

where you add the first term (a1) to the nth term (an), then multiply by n/2

-----------------

As a check, here are the 19 terms listed out and added up. We get 912 like expected.

3+8+13+18 +23+28+33+38 +43+48+53+58 +63+68+73+78 +83+88+93 = 912

There are 19 values being added up in that equation above. I used spaces to help group the values (groups of four; except the last group which is 3 values) so it's a bit more readable.

5 0

3 years ago

Read 2 more answers

Square lMNO is shown in the diagram below what are the coordinates of the midpoint of a diagonal LN

sashaice [31]

Answer:

The coordinates of the midpoint of LN are $(-2\frac{1}{2},4\frac{1}{2})$

answer (4)

Step-by-step explanation:

* Lets explain how to find the midpoint of a line

- The coordinates of the midpoint of a line whose endpoints are (x1 , y1)

and (x2 , y2) are $x=\frac{x_{1}+x_{2}}{2},y=\frac{y_{1}+y_{2}}{2}$

∵ LMNO is a square

∵ The coordinates of point L are (-6 , 1)

∵ The coordinates of point N are (1 , 8)

- Let the coordinates of point L are (x1 , y1) , the coordinates of point

N are (x2 , y2) and the coordinates of the midpoint of LN are (x , y)

∴ x1 = -6 , x2 = 1 and y1 = 1 , y2 = 8

- Use the rule of the midpoint above to find the midpoint (x , y)

∵ $x=\frac{-6+1}{2}=\frac{-5}{2}=-2\frac{1}{2}$

∵ $y=\frac{1+8}{2}=\frac{9}{4}=4\frac{1}{2}$

∴ The coordinates of the midpoint are $(-2\frac{1}{2},4\frac{1}{2})$

* The coordinates of the midpoint of LN are $(-2\frac{1}{2},4\frac{1}{2})$

8 0

3 years ago

Find the product of<br> (-2 x5y3 )( 3x2y )

Y_Kistochka [10]

Answer:

(-2 x5y3 )( 3x2y )= -180 x2 y2

7 0

3 years ago

I’m pretty confused on this question. Anyone know the answers?

Afina-wow [57]

Answer:

see explanation

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

• If m > 0, then the line slopes upwards from left to right ( increases )

• If m < 0, then the line slopes downwards from left to right ( decreases )

(a)

y + x = 3 ( subtract x from both sides )

y = - x + 3 ← in slope-intercept form

with m = - 1 ⇒ decreasing from left to right

(c)

y = 4x + 8 ← is in slope-intercept form

with m = 4 ⇒ increasing from left to right

the equation of a line in the form x = c represents a vertical line, where c is the value of the x-coordinates the line passes through

(b)

x - 5 = 0 ( add 5 to both sides )

x = 5 ← is a vertical line

the equation of a line in the form y = c represents a horizontal line, where c is the value of the y-coordinates the line passes through

(d)

$\frac{y}{4}$ = - 6 ( multiply both sides by 4 )

y = - 24 ← is a horizontal line

3 0

3 years ago