1. 7 and -7 are both 7 units away from 0. They are 14 units away from each other. Absolute value helps because rather than 7+(-7) being 0 absolute value makes anything positive so it becomes 7+7=14 to be able to count the units between the two.
2. 5 and -5 are both 5 units away from 0. They are 10 units away from each other. Absolute value helps because rather than 5+(-5) being 0 absolute value makes anything positive so it becomes 5+5=10 to be able to count the units between the two.
3. 2 and -2 are both 2 units away from 0. They are 4 units away from each other. Absolute value helps because rather than 2+(-2) being 0 absolute value makes anything positive so it becomes 2+2=4 to be able to count the units between the two.
Hope that helps
Answer: 5.17, -0.67
Step-by-step explanation: Solve the equation for p by finding a, b, and c of the qudratic then applying the qquadratic formula
Excact Form: p = 9 + √137/4, 9 - √137/4
Decimal Form:
p = 5.17617497 . . . , -0.67617497 . . .
Hope this helps! :)
~Zane
The formula for the area of a trapezoid is A=1/2(base one+base two)h
All you have to do is find the base one, base two, and height using the given information and then plug it into the equation.
Answer:
B :it is the ratio of the area of the circle to the area of the square from a cross section.
Step-by-step explanation:
had this question on ed2020 and got it right^
