A 95% confidence interval for the proportion of non-fatal accidents involving a distracted driver using some kind of electronic device is 62.5%<x<71.61%
The 95% confidence interval for the proportion is expressed according to the formula;

p is the proportion = 268/400 = 0.67
z is the 95% z-score = 1.96
n is the sample space = 400
Substitute the given parameters into the formula to have:

Hence a 95% confidence interval for the proportion of non-fatal accidents involving a distracted driver using some kind of electronic device is 62.5%<x<71.61%
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15,878,144
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It's B
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