Answer:
26,37
Step-by-step explanation:
m=n-11
m-n=-11-------(1)
m+n+8=71--------(2)
(1)+(2)
(m-n)+(m+n+8)=-11+71
m-n+m+n+8=-11+71
2m+8=60
2m=52
m=26
by substitute in (1)
26-n=-11
-n=-11-26
n=37
Answer:
Step-by-step explanation:
Given
Required
Round up to highest place value
Highest place value here is thousand.
So:
, when approximated
Highest place value here is ten thousand.
So:
, when approximated
Highest place value here is ten thousand.
So:
when approximated
Highest place value here is ten thousand.
So:
when approximated
Highest place value here is ten thousand.
So:
when approximated
Answer:
Step-by-step explanation:
In problems involving proportions, we can use cross products to test whether two ratios are equal and form a proportion. To find the cross products of a proportion, we multiply the outer terms, called the extremes, and the middle terms, called the means.
The maximum number of of bouquets the gardener could have made is 3
<h3>How to find unknown parameter</h3>
Total = 45
let
- number of daffodils = x
- number of tulips = y
Roses = 4x
Tulips = 4x + 15
Total = roses + daffodils + tulips
45 = 4x + x + (4x + 15)
45 = 5x + 4x + 15
45 = 9x + 15
45 - 15 = 9x
30 = 9x
x = 30/9
x = 3.33333333333333
Approximately,
x = 3
Let more about equation:
brainly.com/question/16863577
It'd help if you could sketch this situation. Note that the area of a rectangle is equal to the product of its width and length: A = L W.
Consider the perimeter of this rectangular area. It's P = 2 L + 2 W. Note that P = 40 meters in this problem.
Thus, if we choose to use W as our independent variable, then P = 40 meters = 2 L + 2 W. Let's express L in terms of W. Divide both sides of the following equation by 2: 40 = 2 L + 2 W. We get 20 = L + W. Thus, L = 20 - w.
Then the area of the rectangle is A = ( 20 - W)*W.
Multiply this out. Your result will be a quadratic equation. Graph this quadratic equation (in other words, graph the function that represents the area of the rectangle). For which W value is the area at its maximum?
Alternatively, find the vertex of this graph: remember that the x- (or W-) coordinate of the vertex is given by
W = -b/(2a), where a is the coefficient of W^2 an b is the coefficient of W in your quadratic equation.
Finally, substitute this value of W into your quadratic equation, to calculate the maximum area.
