The angles that share the same tangent value as of tan 45 degrees would be in Quadrant III. This is because in this quadrant the ratios would equal a positive value, which is the same as in the first quadrant, also positive. Tan 45 = 1.
We would need both the x and the y values be either both positive or negative to get a positive final value.
Add the pieces together and then subtract the un shaded region
Answer:
y = -2(x -2)^2 + 11
Step-by-step explanation:
It works well to factor the leading coefficient from the first two terms.
... y = -2(x^2 -4x) +3
Now we want to add the square of half the x-coefficient inside parentheses, and subtract the equivalent quantity outside parentheses.
... y = -2(x^2 -4x +4) +3 - (-2·4)
... y = -2(x -2)^2 +11 . . . . . . . . simplify
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The form given in the problem statement is called "vertex form," where the vertex of the parabola is (h, k). A graph shows us the vertex is (2, 11), so we can write the function immediately as ...
... y = -2(x -2)^2 +11
When using the line, y = -2/5x + 6, the slope of the line is -2/5
The perpendicular line will have the same slope:
In order to write an equation that goes through the point (0, -3), you have to write it in point-slope form.
Point-Slope Form Formula: y - y1 = m(x - x1) (quick note: the letter 'm' represents the slope)
Substitute '-3' for 'y1' and '0' for 'x1'
Answer:
y + 3 = -2/5(x - 0)