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scoundrel [369]

3 years ago

13

The temperature outside dropped 13°F in seven hours. The final temperature was -2°f there tonight what was the starting temperat

ure

2 answers:

aleksley [76]3 years ago

8 0

15 degrees Fahrenheit was the starting temperature!

Juli2301 [7.4K]3 years ago

6 0

13+-2
=-15 you ad the bigger number an subtract the negative number

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Need help with math...

Vilka [71]

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3 years ago

In a scene from a movie, 60 zombies are following a path through the woods, and they end up at one of

Crank

Answer:

waterfall 5 percent

ravine 30

creek 15percent

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4 years ago

Kyla is hiking. She comes to this marker at a fork in the trail. Which of these gives the same distance to Cascade Falls?

gogolik [260]

Answer:

3.5 miles

Step-by-step explanation:

The actual choices and question is as attached. Since it's shown in a mixed fraction as $3\frac{1}{2}$ then we convert the number to decimal. \frac {1}{2} will be 1 divided by 2 which is 0.5 hence the distance to Cascade Falls is 3.5 miles

4 0

3 years ago

Find the velocity and position vectors of a particle that has the given acceleration and the given initial velocity and position

stira [4]

Answer:

$v(t) = (2t+1) \mathbb{i} +3t^2 \mathbb{j} +4t^3 \mathbb{k}$

$r(t) = (t^2+t) \mathbb{i} +(t^3+2) \mathbb{j} +(t^4 - 3) \mathbb{k}$

Step-by-step explanation:

The velocity vector is the integral of the acceleration vector i.e.

$v(t) = \int a(t) dt$

$v(t) = \int (2 \mathbb{i}+6t \mathbb{j} 12t^2 \mathbb{k}) dt$

$v(t) = 2t \mathbb{i}+3t^2 \mathbb{j} 4t^3 \mathbb{k} + C_1$

When $t=0$ , $v(0) = \mathbb{i}$ . Inserting these values in $v(t)$ ,

$C_1= \mathbb{i}$

$v(t) = 2t \mathbb{i}+3t^2 \mathbb{j} 4t^3 \mathbb{k} + \mathbb{i}$

$v(t) = (2t+1) \mathbb{i}+3t^2 \mathbb{j} 4t^3 \mathbb{k}$

The position vector is the integral of the velocity vector i.e.

$r(t) = \int v(t) dt$

$r(t) = \int ((2t+1) \mathbb{i}+3t^2 \mathbb{j} 4t^3 \mathbb{k}) dt$

$r(t) = (t^2+t) \mathbb{i}+t^3 \mathbb{j} t^4 \mathbb{k} + C_2$

When $t=0$ , $r(t) =2\mathbb{j}-3\mathbb{k}$ . Inserting these values in $r(t)$ ,

$C_2=2\mathbb{j}-3\mathbb{k}$

$r(t)= (t^2+t) \mathbb{i}+t^3 \mathbb{j}+ t^4 \mathbb{k} + 2\mathbb{j}-3\mathbb{k}$

$r(t) = (t^2+t) \mathbb{i}+(t^3+2) \mathbb{j}+ (t^4-3) \mathbb{k}$

5 0

4 years ago

Angelina paid $2.70 for 6 juice boxes. how much should angelina expect to pay for 18 juicebox

Gemiola [76]

You will add 2.70+2.70+2.70

6 0

4 years ago

Read 2 more answers