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alina1380 [7]
3 years ago
7

Find the slope of the line that passes through the pair of points

Mathematics
1 answer:
professor190 [17]3 years ago
6 0
Slope= \frac{y_2-y_1}{x_2-x_1} = \frac{-\frac{9}{2} - (-1)}{-2- (-\frac{5}{3})}=\frac{ - \frac{9}{2} +  1}{-2 +   \frac{5}{3}} \\=  \frac{ - \frac{7}{2}}{ - \frac{1}{3}} \\= \frac{ - \frac{7}{2}\cdot6}{ - \frac{1}{3}\cdot6} \\=\frac{-21}{ -2}  \\  =\boxed{\bf{ \frac{21}{2}}}

So... none of your answers are correct. The correct answer is 21/2.
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BRAINLIESTTT ASAP!! PLEASE HELP ME :)
Tju [1.3M]

Answer:

Choice C.

Step-by-step explanation:

A parallelogram is a quadrilateral with two pairs of opposite parallel sides.

There is a theorem that states that opposite sides of a parallelogram are congruent.

In this case, sides AB and CD are opposite sides.

Sides BC and AD are opposite sides.

Side CD is opposite side AB, so they are congruent.

Answer:

Choice C.

CD = AB; Opposite sides of parallelograms are congruent.

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3 years ago
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Because it is made to balance like that.
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3 years ago
Which of the following graphs represents the equation below?: -9x – 3y = -8
Mamont248 [21]
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2 years ago
Consider the functions. F(x)=(x+1)2-4 and g(x)=-4|x+1| which statement compares the range of the functions?
Andreyy89

Answer:

<h2>        The fourth</h2>

Step-by-step explanation:

Vertex of f is (-1, -4) so its range is limited to y≥-4

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3 years ago
(Hehe...Please ignore the markings)
inysia [295]

Answer:

See below:

Step-by-step explanation:

Problem 1:

Multiply Equation 1 by 4, keep Equation 2 the same.

x+y=8, multiply each term by 4:

4*x=4x, 4*y=4y, 8*4=32

so, the equivalent system is: 4x+4y=32 and x-y=2

Solve the system of equations:

x-y=2 becomes x=y+2

plug into 4x+4y=32 to solve for y

4(y+2)+4y=32---> 4y+8+4y=32--->8y=24---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 1 Answer:

Equivalent system: 4x+4y=32, x-y=2; solution: x=5, y=3

Problem 2:

Keep Equation 1 the same. Add 1 and 2.

To add an equation, add the left sides together, and then the rights.

so: x+y=8 + x-y=2 gives us: 2x=10

solve for x ---> 2x/2=10/2--->x=5

plug x into x+y=8--->5+y=8--->y=3

Problem 2 answer:

Equivalent system: x+y=8, 2x=10; solution:x=5, y=3

Problem 3:

Subtract Equation 2 from 1, and keep 2 the same.

To subtract an equation, subtract the left sides, then the rights. We are subtracting 1<em> from </em>2, so its 2-1.

x-y=2 - x+y=8 gives us: -2y=-6

Solve for y by dividing by -2-->-2y/-2=-6/-2---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 3 answer:

Equivalent system: -2y=-6, x-y=2; solution: x=5, y=3

Problem 4:

Multiply the sum of Equation 1 and 2 by a factor of 3. Keep equation 2 the same.

First we add 1 and 2: (we did this earlier) ---> 2x=10 ---> now we multiply it all by 3---> 2x*(3)=10*(3)---> this gives us: 6x=30---> now divide by 6 to solve for x: 6x/6=30/6 gives us: x=5

Now, solve for y by plugging x into equation 2: x-y=2---> 5-y=2--->y=3

Problem 4 answer:

Equivalent system: 6x=30, x-y=2; solution: x=5, y=3

______

Quick Tip: One thing inherent of Equivalent systems is that they have the same set of solutions. Thus, we know the systems are equivalent when they have the same set of solutions for x and y. Moreover, you don't need to solve every time after you attempt to find an equivalent system, instead, just plug in the values found in problem 1 to each new set of equations to test if they are equivalent.

If we find x=5 and y=3 for x+y=8 and x-y=2, then all we have to do is plug them in to 6x=30 and -2y=-6 to see if they are equivalent.

6(5)=30 ---> true

-2(3)=-6 ---> true

3 0
3 years ago
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