This is the concept of probability, we are required to calculate for the probability of rolling a 4 with a single die four times in a row;
To solve this we proceed as follows;
The probability space of a die is x={1,2,3,4,5,6}
The probability of a die falling on any of this number is:
P(x)=1/6
Thus the probability of rolling a 4 with a single die four times which makes up mutually exclusive events will be:
1/6*1/6*1/6*1/6
=(1/6)^4
=1/1296
The answer is B] 1/1296
Answer:
a) 400 meters
b) 67 meters
c) 124.790 meters
Step-by-step explanation:
Given data :
g1 = - 0.4 %
g2 = +2 %
change of grade of sag curve ( a ) = 0.6 %
Elevation of PVI ( h2 ) = 124.80 m
a) compute the length of the curve using the relation below
a = . hence ; L = ( g2 - g1 ) / a
L = ( 2 -(-0.4 ) / 0.6
= 2.4 / 0.6 = 4
= <em>400 meters</em>
<u>b) compute the elevation of the lowest point of the curve</u>
slope of the vertical curve = 0
0 = 2ax l + b
= 2( ) x + g1
∴ x = = ( 0.4 * 4 ) / ( 2 + 0.4 ) = 1.6 / 2.4 = 0.67 stations
therefore x ( elevation of the lowest point ) = <em>67 meters</em>
C<u>) compute the elevation at Sta. 12 + 125.60</u>
Given that the rate of change of elevation is the same at all points
= = 0.4 -------- ( 1 )
where h2 = 124.80
h1 = ? ( elevation of p0 ) at 12 + 125.60
PVI = 12 + 150.06
p0 = 12 + 125.60
back to the above equation
- h1 = 0.4 ( PVI - P0 ) - h2
= 0.4 ( 12.150 - 12.1256 ) - 124.80
-h1 = -124.790
hence h1 = 124.790 m
Answer:
Let, height of the Building = x
Height of the Tower = y
Height of the tower is 5 times from height of the building = y = 5x
Height of the tower is 52 meter taller than the building = y-x = 52
put 5x instead of y in the equation y-x=52
5x-x=52
4x=52
x=52/4
x=13 meter
y=5x
y=5(13)
y=65 meter
4x - 7 x = 6
4(6) - 7
24 - 7
17
Answer: 17
Hope this helps :)
Please give brainliest