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pav-90 [236]
3 years ago
13

Find a function that models the population after t years

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
5 0
A) You have:

f(0) = 270000\\ f(1) = 1.04f(0), \\ f(2) = 1.04f(1) = 1.04(1.04f(0)), \\ f(t) = 1.04f(t-1) = 1.04(1.04f(t-2)) ... = 1.04^{t}f(0) = 1.04^{t}*270000

b) f(2004-1998) = 1.04^{2004-1998} * 270000 = 341636

c)
1.04^{x-1998} * 270000 \geq 534094
 \\ 
x - 1998  \geq {ln( \frac{534094}{270000} )}/{ln(1.04)}
 
x  \geq 2015.4

x = 2016
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alexandr1967 [171]

Answer:

y=-4/2x+-2

Step-by-step explanation:

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4 years ago
If y(x)=4x what is x when y(x)=4?​
Fofino [41]

Answer:

1

Step-by-step explanation:

y(x)=4x

y(x)=4

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4 0
3 years ago
Determine whether the systems have one solution, no solution, or infinitely many solutions
Lerok [7]

Answer:

First system: no solution

Second system: one solution

Third system: one solution

Fourth system: infinite solutions

Fifth system: no solution

Step-by-step explanation:

First system: 3x-2y=3; 6x-4y=1

From the first equation: y = (3x - 3)/2

Using this value of y in the second equation:

6x - 6x + 6 = 1

6 = 1 -> System has no solution

Second system: 3x-5y=8; 5x-3y=2

From the first equation: x = (8 + 5y)/3

Using this value of x in the second equation:

5*(8 + 5y) - 9y = 6

40 + 25y - 9y = 6

16y = -34 -> y = -2.125

x = (8 - 5*2.125)/3 = -0.875

This system has one solution

Third system: 3x-2y=8; 4x-3y=1

 From the first equation: x = (8 + 2y)/3

Using this value of x in the second equation:

4*(8 + 2y) - 9y = 3

32 + 8y - 9y = 6

y = 26

x = (8 + 2*26)/3 = 20

This system has one solution

Fourth system: 3x-6y=3; 2x-4y=2

  From the first equation: x = 1 + 2y

Using this value of x in the second equation:

2*(1 + 2y) - 4y = 2

2 + 4y - 4y = 2

2 = 2

This system has infinite solutions

Fifth system: 3x-4y=2; 6x-8y=1

  From the first equation: x = (2 + 4y)/3

Using this value of x in the second equation:

2*(2 + 4y) - 8y = 1

4 + 8y - 8y = 2

4 = 2

This system has no solution

5 0
3 years ago
Justin drinks 1 litter of water.He drank 2,000 litters at his game.How many during his game and his practice?Explain.
djverab [1.8K]

The question is incomplete. The complete question is :

Justin drinks 1 litter of water during the soccer practice. He drank 2,000 milliliters of water at his game. How many liters of water did he drink during his game and his practice? Explain.

Solution :

It is given that :

During practice, Justine drank = 1 liter of water

During game, Justine drank = 2000 milliliters of water

We know that,

1 liter = 1000 mL

Therefore, during the game, Justine drank :

1000 mL = 1 liter

∴ 2000 mL = 2 liter

So Justine drank 2 liters of water during his soccer game and 1 liter of water during his practice.

7 0
3 years ago
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