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omeli [17]
3 years ago
8

Name the diameter for the circle Q. A. QH. B.EH. C.HC. D.QE

Mathematics
2 answers:
Alisiya [41]3 years ago
3 0

Answer:

B) EH

Step-by-step explanation:

almond37 [142]3 years ago
3 0

Answer:

QH = radius

EH = Diameter

QE = radius

Step-by-step explanation:

<h2>NOTE</h2>

The diameter is the full length dividing the circle into two equal halfs

Where as the radius divides the diameter into two halfs

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The scale of a map says that 2 in represents 10 miles. What distance on th map (in centimeters) represents an actual distance of
NNADVOKAT [17]

Answer:

8 inches

Step-by-step explanation:

Step 1:

2 : 10 miles     Ratio Inches to Miles

Step 2:

2 : 10 = x : 40     Equation

Step 3:

10x = 80    Multiply

Step 4:

80 ÷ 10   Divide

Answer:

x = 8

Hope This Helps :)

8 0
4 years ago
Drag and drop the numbers into the boxes to create an expression that is equivalent to the given expression.
slega [8]
5c + 30 because you use the distributive property 5 x c + 5 x 6
3 0
3 years ago
Can you guys help me I need help
dem82 [27]

Answer:

182m^2

Step-by-step explanation:

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Hope this helps.

3 0
3 years ago
Find the three arithmetic means in this sequence. 12 __ __ __ 40
Lena [83]
To answer this question first you have to count the difference between the highest number with the lowest number.
In this case, the difference is: 40-12=28

After that, you need to determine the leaps in the sequence. In this case, there are 4 leaps.  
After that divide the difference with the leaps : 28:4=7
Therefore the sequence will be 12 , 19, 26, 33, 40
6 0
4 years ago
There are five consecutive odd integers. The sum of the three smallest is 3 more than the sum of the two largest. Find the integ
Cerrena [4.2K]

Answer:

11 13 15 17 19

Step-by-step explanation:

We will solve this word problem using 2k+1 which is one of the general forms of an odd integer.

Let 2k+1 be the first odd integer.

(2k+1) + (2k+3) + (2k +5) =  (2k+7) + (2k +9) + 3 (the +3 is to accommodate for the left side being 3 more than the right)

Solve for k

6k + 9 = 4k + 19

6k - 4k + 9 = 4k-4k + 19

2k + 9 = 19

2k + 9 - 9 = 19 - 9

2k = 10

2k/2 = 10/2

k = 5

To get the first digit in the series plug in 5 for k

2k+1

2(5) + 1

10 + 1 = 11

So our series is 11, 13, 15, 17, 19

Let's test it.

11 + 13 +15 = 39

17 + 19 = 36

So we are correct, the first 3 integers are 3 more that the sum of the last 2.

6 0
3 years ago
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