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omeli [17]
3 years ago
8

Name the diameter for the circle Q. A. QH. B.EH. C.HC. D.QE

Mathematics
2 answers:
Alisiya [41]3 years ago
3 0

Answer:

B) EH

Step-by-step explanation:

almond37 [142]3 years ago
3 0

Answer:

QH = radius

EH = Diameter

QE = radius

Step-by-step explanation:

<h2>NOTE</h2>

The diameter is the full length dividing the circle into two equal halfs

Where as the radius divides the diameter into two halfs

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Could you please help me thank you
stiks02 [169]

Answer:

2 (1/3) cups

Step-by-step explanation:

8 x 3(1/2) = 28 cups

28 / 12 = 2 (1/3) cups

3 0
3 years ago
Which best describes the association between variables x and y?
erik [133]
Your answer is : B hope this helps
5 0
4 years ago
Read 2 more answers
If function g has the factors (x - 7) and (x + 6), what are the zeros of function g?
SVEN [57.7K]

Answer:

7 and -6

Step-by-step explanation:

Given

Factors: (x - 7) and (x + 6)

Required

Determine the zeros

To do this, we simply equate the factors to 0

x - 7 = 0

x = 7

x + 6 = 0

x = -6

<em>So, the zeros are -7 and 6</em>

5 0
3 years ago
Factor completely x^2-48
fredd [130]

Answer: (x-7)(x+7)


Step-by-step explanation:

To solve this problem you must apply the proccedure shown below;

- Make the equation equal to zero:

x^{2}-49=0

-Add 49 at both sides:

x^{2}=49

- Now, you must take the square root of both sides of the equation, then you obtain the following roots:

x=\sqrt{49}\\x_1=7\\x_2=-7

- Then you have:

x^{2}-49=(x-7)(x+7)

5 0
4 years ago
(-1, -7), 3x + 12y = -6 find the perpendicular line
mojhsa [17]

Step-by-step explanation:

write equation in terms of x

y=(-6+3x)/12

from this equation u can see your gradient is 3/12 or 1/4

your perpendicular gradient is -1/m (m being the gradient of your main line)

so gradient of perpendicular= -4

since coordinate of main line is given, that point will also be on perpendicular.

so u have point and gradient so u can Calculate line equation

Y=MX+C

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y=-4x-11

^equation of perpendicular

5 0
3 years ago
Read 2 more answers
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