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ss7ja [257]
3 years ago
7

MATH HELP PLEASE!!!!!!!!!!!!!

Mathematics
1 answer:
STALIN [3.7K]3 years ago
5 0
The answer is:  [C]:  " f ⁻¹(x) = (5x + 3) / 2 " .
______________________________________________________
Explanation:
______________________________________________________
Given:  "f(x) = (2x - 3) / 5 ;  which is the "inverse" of:  " f(x)" ?

Substitute "y" for "f(x)" :

y = (2x - 3) / 5 ; 

Replace "x" with "y"; and "y" with "x" ; and rewrite:

x = (2y - 3) / 5 ; 

Now,  solve for "y" , in term of  "x'  ;

Multiply each side of the equation by "5" 

5 * x = 5 * { (2y - 3) / 5 } ; 

to get:

5x = 2y - 3 ;  

Add "3" to each side of the equation:

5x + 3 = 2y - 3 + 3 ; 

to get:  5x + 3 = 2y ; 

↔  2y = 5x + 3 ; 

Divide each side of the question by "2" ; 
      to isolate "y" on one side of the equation; & to solve for "y" in terms of "x" ; 

   → 2y / 2 = (5x + 3) / 2 ; 

to get:  y = (5x + 3) / 2 ;  

Replace the "y" with:  " f ⁻¹(x) " ; 

and rewrite:

" f ⁻¹(x) = (5x + 3) / 2 " ;

→  which is:  "Answer choice:  [C]:  " f ⁻¹(x) = (5x + 3) / 2 " .
__________________________________________________

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One year Thomas had the lowest ERA (earned-run average, mean number of runs yielded per nine inning pitched) of any male pitcher
valkas [14]

Answer:

Thomas had an ERA with a z-score of -2.82.

Karla had an ERA with a z-score of -2.81.

Thomas had the better year compared with his peers, since his ERA had the lower Zscore.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

The ERA is the Earned Runs Average per 9 innings. This mean that the lower the ERA is, the better it is. So, between Thomas and Karla, whoever has the lower Zscore had the better season.

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Thomas ERA was 3.31. This means that X = 3.31

Z = \frac{X - \mu}{\sigma}

Z = \frac{3.31 - 4.837}{0.541}

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Thomas had an ERA with a z-score of -2.82.

Karla

For Females, the mean ERA was 4.533 and the standard deviation was 0.539. This means that \mu = 4.533, \sigma = 0.539.

Karla ERA was 3.02. So X = 3.02.

Z = \frac{X - \mu}{\sigma}

Z = \frac{3.02 - 4.533}{0.539}

Z = -2.81

Karla had an ERA with a z-score of -2.81

Which player had a better year in comparison with their peers?

Thomas had the better year compared with his peers, since his ERA had the lower Zscore.

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