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3 years ago

Calculate the area and perimeter plz help

Mathematics

1 answer:

kramer3 years ago

7 0

Answer:

Figure 1:

Area: 30m^2

Perimeter: 23.6m

Figure 2:

Area: 98.8km^2

Perimeter:56.5km

Step-by-step explanation:

Area is base x height.

To get the perimeter, add up all the sides.

Figure 1:

Area:

6x5=30m^2

Perimeter: 6+5.8+6+5.8=23.6m

Figure 2:

Area:

7.6x13 = 98.8km^2

Perimeter:7.6+15+20+13.9=56.5km

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ladessa [460]

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2 years ago

What are the values of x and y

NeTakaya

Answer:

x = 16

y = 131

Step-by-step explanation:

4x + 2x - 6 = 90

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x = 16

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7 0

3 years ago

Find, correct to four decimal places, the length of the curve of intersection of the cylinder 4x2 1 y2 − 4 and the plane x 1 y 1

charle [14.2K]

Answer- Length of the curve of intersection is 13.5191 sq.units

Solution-

As the equation of the cylinder is in rectangular for, so we have to convert it into parametric form with

x = cos t, y = 2 sin t (∵ 4x² + y² = 4 ⇒ 4cos²t + 4sin²t = 4, then it will satisfy the equation)

Then, substituting these values in the plane equation to get the z parameter,

cos t + 2sin t + z = 2

⇒ z = 2 - cos t - 2sin t

∴ $\frac{dx}{dt} = -\sin t$

$\frac{dy}{dt} = 2 \cos t$

$\frac{dz}{dt} = \sin t-2cos t$

As it is a full revolution around the original cylinder is from 0 to 2π, so we have to integrate from 0 to 2π

∴ Arc length

$= \int_{0}^{2\pi}\sqrt{(\frac{dx}{dt})^{2}+(\frac{dy}{dt})^{2}+(\frac{dz}{dt})^{2}$

$=\int_{0}^{2\pi}\sqrt{(-\sin t)^{2}+(2\cos t)^{2}+(\sin t-2\cos t)^{2}$

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$

Now evaluating the integral using calculator,

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$ $= 13.5191$

8 0

3 years ago

HELP PLS ASAP!!!! PLS

Reptile [31]

Answer:

x=3

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Y=3/2x-1 -6x+4y=-4 Does this have no solution or infinitely many solutions please explain.

Aleks04 [339]

Answer:

infinitely many solutions

Step-by-step explanation:

Let's eliminate the fractional coefficient in the first equation by multiplying that equation by 4:

4y = 6x - 4

The second equation can be rewritten as 4y = 6x - 4, so the two equations are actually identical. They have infinitely many solutions.

6 0

3 years ago