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3 years ago

Calculate the area and perimeter plz help

Mathematics

1 answer:

kramer3 years ago

7 0

Answer:

Figure 1:

Area: 30m^2

Perimeter: 23.6m

Figure 2:

Area: 98.8km^2

Perimeter:56.5km

Step-by-step explanation:

Area is base x height.

To get the perimeter, add up all the sides.

Figure 1:

Area:

6x5=30m^2

Perimeter: 6+5.8+6+5.8=23.6m

Figure 2:

Area:

7.6x13 = 98.8km^2

Perimeter:7.6+15+20+13.9=56.5km

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-2x + 7<br> Coefficient(s) :<br> Variables(s):<br> Constant:

Serggg [28]

Answer:

Variable = x

Coefficient = 2

Constant = 7

A variable is an unknown that holds an unknown value.

A coefficient is a number that multiplies something.

A constant is a fixed number.

Hope This Helps :)

4 0

3 years ago

4 days I have 140 copies of a book, 9 days I only have 50 left. Write an equation where c(t)=my+b where c is number of copies st

alexandr402 [8]

Answer:

$c(t)=-18t+212$ .

Step-by-step explanation:

We have been given that 4 days I have 140 copies of a book, 9 days I only have 50 left. We are asked to write an equation $c(t)=my+b$ , where c is number of copies still on hand and t days being available.

We have two points on line (4,140) and (9,50). Now, we will use these points to find slope as:

$m=\frac{140-50}{4-9}$

$m=\frac{90}{-5}$

$m=-18$

Now, we will use point-slope form of equation $y-y_1=m(x-x_1)$ and substitute $m=-18$ and coordinates of point (9,50) as:

$y-50=-18(x-9)$

$y-50=-18x+162$

$y-50+50=-18x+162+50$

$y=-18x+212$

Therefore, our required equation would be $c(t)=-18t+212$ .

5 0

3 years ago

Can any one figure this out?

lions [1.4K]

X = 7/3
Because 16^1.66667 = 101.593 and 4^3.33333 = 101.593

4 0

3 years ago

((Pls help need then to get my grade up))

DIA [1.3K]

It's C because the equations are similar

3 0

3 years ago

What is the perimeter of ΔABC?

Serggg [28]

Answer:

Choice D: Perimeter = 5 + $\sqrt{65}$ + $\sqrt{34}$ units

Step-by-step explanation:

point B(9, 2) , point C(4, 5), point A (1,1)

Perimeter = D( A, C) + D (A, B) + D (B, C)

where D (A, C) = distance between A and C

so...

D(A, C) = root ( (4 - 1)^2 + (5 - 1)^2) = 5 from a 3-4-5 right triangle.

D(A, B) = root( (9- 1)^2 + (2 -1)^2) = root( 64 + 1) = root(65)

D(B, C) = root( (9 -4)^2 + (2 -5)^2) = root (25 + 9) = root(34)

Perimeter = 5 + root(65) + root(34)

Perimeter = 5 + $\sqrt{65}$ + $\sqrt{34}$ units

6 0

3 years ago