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LiRa [457]
3 years ago
8

A woman with type o blood is expecting a child. her husband is type

Biology
1 answer:
masya89 [10]3 years ago
6 0
Woman's genotype: ii
Husband's genotype: I^A i
-> possible husband's father genotypes are two I^B and I^B i
-> if husband's father has two I^B alleles, the husband will have one I^B allele present, which is not the case. So, there is i allele present. (can also infer that I^A comes from husband's mother)

Child's possible genotypes:
ii, ii, I^A i, I^A i
probability is 1/2
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lesantik [10]

Answer:

Asking students to wash their hands on routine basis and also to keep the area clean.

Explanation:

Hand sanitization is very important and hence considered as a primary step to control infection. Students should wash their hands on routine basis. Also, they should keep the area clean.

7 0
3 years ago
In the Calvin cycle the conversion of energy poor carbon dioxide into energy rich glucose
rodikova [14]

Answer:

D)NADPH is made

A)ATP is used

Explanation:

Sorry to ask the two questions, I asked why the two options are in the process:Reduction. In the second stage, ATP and NADPH are used to convert the 3-PGA molecules into three-carbon sugar molecules, glyceraldehyde-3-phosphate ( G3P ). At this stage, it gets its name because NADPH donates, or reduces , electrons to a three-carbon intermediate to form G3P.[Ocultar detalhes]

The reduction stage of the Calvin cycle, which needs ATP and NADPH, converts 3-PGA (produced in the fixation stage) into a three-carbon sugar. This process takes place in two main stages:

Simplified diagram of the reduction step of the Calvin cycle showing the carbon atoms, but not the complete molecular structures. A 3-PGA molecule first receives a second phosphate group from ATP (generating ADP). Then, the doubly phosphorylated molecule receives electrons from NADPH and is reduced to form glyceraldehyde-3-phosphate. This reaction generates NADP + and also releases an inorganic phosphate.

Simplified diagram of the reduction step of the Calvin cycle showing the carbon atoms, but not the complete molecular structures. A 3-PGA molecule first receives a second phosphate group from ATP (generating ADP). Then, the doubly phosphorylated molecule receives electrons from NADPH and is reduced to form glyceraldehyde-3-phosphate. This reaction generates NADP + and also releases an inorganic phosphate.

First, each 3-PGA molecule receives a phosphate group from ATP, becoming a doubly phosphorylated molecule called 1,3-bisphosphoglyceride (and leaving an ADP as a by-product).

Second, 1,3-bisphosphoglycerate molecules are reduced (gain electrons). Each molecule receives two electrons from NADPH and loses one of its phosphate groups, becoming a three-carbon sugar called glyceraldehyde-3-phosphate (G3P) . This step produces NADP^+

+

start superscript, plus, end superscript and phosphate (\text P_iP

i

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The chemical structures and real reactions are:

Reactions of the Calvin cycle reduction step, showing the molecular structures of the molecules involved.

Reactions of the Calvin cycle reduction step, showing the molecular structures of the molecules involved.

The ATP and NADPH used in these steps are products of the photo-dependent reactions (first stage of photosynthesis). That is, the chemical energy of ATP and the reducing potential of NADPH, both produced with the use of light energy, keep the Calvin cycle running. Conversely, the Calvin cycle regenerates ADP and NADP^+

+

start superscript, plus, end superscript, providing the necessary substrates for photo-dependent reactions.

7 0
3 years ago
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Answer:

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3 years ago
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3 years ago
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Answer:

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7 0
2 years ago
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