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earnstyle [38]
3 years ago
7

The first part of cellular respiration occurs in these compartments of the cell. ______________

Biology
1 answer:
Mandarinka [93]3 years ago
3 0

Answer:

The correct answer is - cytoplasm of the cell.

Explanation:

Cellular respiration is the bunch of metabolic reactions that convert biochemical energy from the glucose or other nutrients into ATP ( adenosine triphosphate) and releases water and carbon dioxide as waste products.

This process has three stages and the very first stage is glycolysis which is taking place in the cytoplasm of the cell. In this stage, the glucose molecule converts into the two molecules of pyruvate and produce energy.

Thus, the correct answer is - cytoplasm of the cell.

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We have about ______ as many genes as a fruit fly.
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Almost twice

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Human being have estimate 24,000 genes, while fruit flies have an estimate of 14,000 genes: meaning it is almost twice

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Basalt is a rock that cooled quickly after lava erupted do a volcano what is the best description of its texture
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The immunoglobulin light chain does not have a D segment. In humans, there are two different possible light chain proteins, term
wlad13 [49]

Answer:

295  

Explanation:

Antibodies (also known as immunoglobulins) are immune system-related proteins that circulate in the bloodstream in order to recognize pathogenic harmful substances (antigens) and neutralize them. An antibody consists of two immunoglobulin heavy chains and two immunoglobulin light chains. There are two types of immunoglobulin light chains: 1-the kappa (κ) light chain, which is encoded by the immunoglobulin κ locus; and 2-the lambda (λ) light chain, which is encoded by the immunoglobulin λ locus. The immunoglobulin light chain is a multidomain protein composed of two domains: 1- the N-terminal variable (V) domain and 2-the C-terminal constant (C) domain. V(D)J recombination is a type of somatic rearrangement process by which T and B cells can assemble different gene segments, which are referred to as variable (V), diversity (D) and joining (J) gene segments. In the question above the number of possible genomic recombination events between immunoglobulin gene segments can be calculated as >> (5 x 35) + (4 x 30) = 295.

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Hope this helps!

-Payshence xoxo



3 0
3 years ago
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