1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Margaret [11]
3 years ago
6

find the probability of getting 4 consecutive aces when four cards are drawn without replacement from a standard deck of 52 play

ing cards
Mathematics
1 answer:
Paraphin [41]3 years ago
4 0
There are 4 aces in a deck of 52 cards

probability of 1st card being an ace = 4/52
without replacement
probability of 2nd card being an ace = 3/51
without replacement
probability of 3rd card being an ace = 2/50
without replacement
probability of 4th card being an ace = 1/49

probability of all 4 cards being aces : 4/52 * 3/51 * 2/50 * 1/49 =
24/6,497,400 reduces 1/270,725
You might be interested in
•allie's walking rate is 2 meters per second Allie's house is 200 meters from the fountain
Alborosie
r=\frac{d}{t}\ \ \to\ \ t=\frac{d}{r}\\\\t=\frac{200}{2}=100s\\\\It\ will\ take\ 100\ seconds
7 0
3 years ago
One cat travels 4.5 meters in 1.5 seconds. Another cat travels 11.7 meters in 4.5 seconds?
kap26 [50]
What are we trying to find in this problem? Add details please
8 0
2 years ago
Read 2 more answers
The mean of the following numbers is 15. 14,10,18,,21,15,14​
Leona [35]

Answer:

= 15.285714285714

Step-by-step explanation:

6 0
3 years ago
The probability of drawing a red candy at random from a bag of 25 candies is 2/5. After 5 candies are removed from tehe bag, wha
yaroslaw [1]

Given:

The probability of drawing a red candy at random from a bag of 25 candies is \dfrac{2}{5}.

To find:

The probability of randomly drawing a red candy from the bag after removing 5 candies from the bag.

Solution:

Let n be the number of red candies in the bag. Then, the probability of getting a red candy is:

P(Red)=\dfrac{\text{Number of red candies}}{\text{Total candies}}

\dfrac{2}{5}=\dfrac{n}{25}

\dfrac{2}{5}\times 25=n

10=n

After removing the 5 candies from the bag, the number of remaining candies is 25-5=20 and the number of remaining red candies is 10-5=5.

Now, the probability of randomly drawing a red candy from the bag is:

P(Red)=\dfrac{5}{20}

P(Red)=\dfrac{1}{4}

Therefore, the required probability is \dfrac{1}{4}.

3 0
3 years ago
The restraunt bill is $56.39 what is a tip for 20% of bill
ikadub [295]
$11.28 so in total it would be $67.67
7 0
3 years ago
Read 2 more answers
Other questions:
  • I need to turn 16/3 into a proper fraction
    12·2 answers
  • Distance between points (0,6) (2,3) <br><br> Square root 13<br><br> 5<br><br> Square root 73
    14·1 answer
  • Product of primes for 63
    10·1 answer
  • Sam left for school at 8:00, walking at a speed of 2 mph. Soon after, his father discovered that Sam left behind his project tha
    6·1 answer
  • On Tuesday a bookstore sold 50 books.On Wednesday the bookstore sold 150 books.The bookstore must sell 500 books by Friday.Creat
    12·2 answers
  • Please answer this someone! 2x3/4
    5·2 answers
  • PLEASEE HELPP WILL BRAINLIST Find the output when x = 0
    8·1 answer
  • Which property can be used to solve the equation?
    12·2 answers
  • Help me out please thanks
    11·1 answer
  • A group of middle and high school students are surveyed as to their breakfast preferences. The results are shown below.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!