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meriva
2 years ago
14

A group of middle and high school students are surveyed as to their breakfast preferences. The results are shown below.

Mathematics
1 answer:
Aleks04 [339]2 years ago
3 0

The probability a randomly selected student eats breakfast is 0.58.

The probability a randomly selected student is a middle schooler is 0.60.

The probability a randomly selected student is either a high schooler OR eats breakfast is 0.98.

The probability a randomly selected student is a high schooler AND eats breakfast is 0.23.

The probability a randomly selected student is a high schooler, given that they eat breakfast is 0.33.

The probability a randomly selected student eats breakfast given the student is a high schooler is 0.23.

<h3>What are the probabilities?</h3>

The probability a randomly selected student eats breakfast = number of students that eat breakfast / total number of students

52 / (52 + 38) =  0.58.

The probability a randomly selected student is a middle schooler = total number of middle schoolers / total number of students = (40 + 14) / 90 =  0.60.

The probability a randomly selected student is either a high schooler OR eats breakfast = (total number of high schoolers / total number of students) + (number of students that eat breakfast / total number of students) = 36 / 90 + 52 / 90 =  0.98.

The probability a randomly selected student is a high schooler AND eats breakfast = (total number of high schoolers / total number of students) x (number of students that eat breakfast / total number of students) = 36 / 90 x 52 / 90 =  0.23.

The probability a randomly selected student is a high schooler, given that they eat breakfast = high schooler that eats breakfast / total number of students that eat breakfast

12 / 52 =  0.33.

The probability a randomly selected student eats breakfast given the student is a high schooler = high schooler that eats breakfast / total number of high schoolers = 12 / 36 = 0.23.

To learn more about probability, please check: brainly.com/question/13234031

#SPJ1

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Answer:

CV for A = 21.8%

CV for B = 15.5%

Step-by-step explanation:

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Since the orange juice container that has a capacity of 16 ounces states that it has 200 milligrams of vitamin C, this means that it fulfills 250% of an adult's recommended daily requirement for vitamin C. Then, for one hundred percent of the daily allotment,

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