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Bezzdna [24]
3 years ago
15

I really need help with this. I'd really appreciate anyone's help.

Mathematics
1 answer:
vekshin13 years ago
4 0

Answer:

I think it's G

Step-by-step explanation:

Since a=8 root 3=8×3=24cm

Yh so I multiplied the 24cm by 12cm

12cm×24cm=288cm squared

and the square root of 288cm is 96 root 3 cm squared

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One desk requires 84 inches of a type of trim. Find the lenght of trim needed in inches of 5 desks. Then convert yours answer to
Crazy boy [7]

420 inches and 35 feet

length of trim required = 84 × 5 = 420 inches

using 12 inches = 1 foot then

\frac{420}{12} = 35 feet


6 0
3 years ago
Mario transferred a balance of $6050 to a new credit card at the beginning of
Kryger [21]

Answer:

the answer is (6050){1+0.031/12}^3{1+0.206/12}^9 for APEX

Step-by-step explanation:

7 0
2 years ago
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Evaluate the value of the expression<br>4(x+2-5x) when x=2​
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Step-by-step explanation:

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2 years ago
Given right triangle QRS, what is the value of sin(30°)? StartFraction StartRoot 3 EndRoot Over 3 EndFraction One-half StartFrac
baherus [9]

Answer:

Option 2: \sin(30)=\frac{1}{2}

Step-by-step explanation:

Given:

From the triangle shown below;

A triangle QRS with angle QRS = 90°, ∠QSR = 30°.

Side QR = 5, SQ = 10 and RS = 5√3

Now, we know from trigonometric ratio that,

\sin (A) = \frac{Opposite\ side}{Hypotenuse}

Here, opposite side of angle QSR is QR and Hypotenuse is the side opposite angle QRS which is SQ. Therefore,

\sin(\angle QSR)=\dfrac{QR}{SQ}\\\\\\\sin(30)=\dfrac{5}{10}\\\\\\\sin(30)=\dfrac{5}{2\times 5}=\dfrac{1}{2}

Therefore, the value of sine of 30° is one-half. So, second option is correct.

6 0
3 years ago
Read 2 more answers
Calculate two iterations of Newton's Method for the function using the given initial guess. (Round your answers to four decimal
pickupchik [31]

Answer:

The first and second iteration of Newton's Method are 3 and \frac{11}{6}.

Step-by-step explanation:

The Newton's Method is a multi-step numerical method for continuous diffentiable function of the form f(x) = 0 based on the following formula:

x_{i+1} = x_{i} -\frac{f(x_{i})}{f'(x_{i})}

Where:

x_{i} - i-th Approximation, dimensionless.

x_{i+1} - (i+1)-th Approximation, dimensionless.

f(x_{i}) - Function evaluated at i-th Approximation, dimensionless.

f'(x_{i}) - First derivative evaluated at (i+1)-th Approximation, dimensionless.

Let be f(x) = x^{2}-8 and f'(x) = 2\cdot x, the resultant expression is:

x_{i+1} = x_{i} -\frac{x_{i}^{2}-8}{2\cdot x_{i}}

First iteration: (x_{1} = 2)

x_{2} = 2-\frac{2^{2}-8}{2\cdot (2)}

x_{2} = 2 + \frac{4}{4}

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Second iteration: (x_{2} = 3)

x_{3} = 3-\frac{3^{2}-8}{2\cdot (3)}

x_{3} = 2 - \frac{1}{6}

x_{3} = \frac{11}{6}

7 0
3 years ago
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