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Anton [14]
2 years ago
10

3 consecutive odd integers such that the sum of twice the first and three times the second is 55 more than twice the third

Mathematics
1 answer:
den301095 [7]2 years ago
3 0

Answer:

Consecutive odd integers are 19 , 21 & 23

Step-by-step explanation:

Let the first 3 consecutive odd intergers be x , (x + 2) and (x + 4).

According to the question,

2x + 3(x + 2) = 2(x + 4) + 55

=  > 2x + 3x + 6 = 2x + 8 + 55

Eliminating 2x from both the sides,

=  > 3x + 6 = 63

=  > 3x = 63 - 6 = 57

=  > x =  \frac{57}{3}  = 19

So, the consecutive odd integers are = 19 , 21 & 23.

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What is the symbol for 1.020____1.200<br> A:&lt;<br> B:&gt;<br> C:=
slega [8]

Answer:

A

Step-by-step explanation:

1.020 is less than 1.200

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On the day after my birthday this year, I can truthfully say: "The day after tomorrow is Monday". On which day is my birthday?
andriy [413]

Answer: Friday

Step-by-step explanation:

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1 year ago
State the probability that justifies each statement.<br><br>11. If 2x+19=27, then 2x=8​
Liono4ka [1.6K]

Answer:

100% true....

subtracting 19 from both sides brings you to 2x=8, so x=4

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Sub 2 my channel: Siah Fiah
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no

Step-by-step explanation:

From left to right, follow the dots in line 1 with your finger. Count a steady beat out loud, and time your motion so your finger crosses a dot at the end of each beat. Don’t pause at the dots, and move as smoothly as you can. A good way to count is to say or think “1 Mississippi, 2 Mississippi,” and so on. Is your finger moving at a constant rate, or is the rate changing?

7 0
2 years ago
Read 2 more answers
(a) What is wrong with the following equation? x2 + x − 42 x − 6 = x + 7 (x − 6)(x + 7) ≠ x2 + x − 42 The left-hand side is not
jeka94

Answer:

Attached please find answer

Step-by-step explanation:

= (x² + x - 42) / (x - 6)

= [x² + (7x - 6x) - 42] / (x - 6)

= [x² + 7x - 6x - 42] / (x - 6)

= [(x² + 7x) - (6x + 42)] / (x - 6)

= [x(x + 7) - 6(x + 7)] / (x - 6)

= [(x + 7)(x - 6)] / (x - 6)

= x + 7 → when x approches 6

= 6 + 7

= 13

Other method:

Lim   (x² + x - 42) / (x - 6)

x→ 6

When x → 6, there is an indeterminate expression because: 6 - 6 = 0

Do you know the l'Hôpital's rule, when x → a:

Lim [ f(x) / g(x) ] = Lim [ f'(x) / g'(x) ]

f(x) = x² + x - 42

f'(x) = 2x + 1

g(x) = x - 6

g'(x) = 1

= f'(x) / g'(x)

= (2x + 1)/1

= 2x + 1 → when x approches 6

= 12 + 1

= 13

3 0
2 years ago
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