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Otrada [13]
3 years ago
15

Divide. Write your answer as a decimal.

Mathematics
1 answer:
Lynna [10]3 years ago
5 0
Sent a picture of the solution to the problem (s).

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O comprimento de um retângulo é 6x e sua largura é 5y. A) Escreva uma expressão algébrica que representa o perímetro desse retân
Kobotan [32]

Answer:

A) 12x + 10y

B) 118cm

Step-by-step explanation:

A) A fórmula para calcular o perímetro de um retângulo é dada como:

Perímetro de um retângulo = 2 (L + W)

= 2L + 2W

Onde

L = comprimento do retângulo

W = largura do retângulo

A) A pergunta nos diz que:

O comprimento de um retângulo é 6x e sua largura é 5y.

A expressão algébrica que representa o perímetro do retângulo =

Perímetro de um retângulo = 2 (L + W)

= 2L + 2W

L = 6x, W = 5y

= 2 (6x) + 2 (5y)

= 12x + 10y

A expressão algébrica que representa o perímetro do retângulo é

P = 12x + 10y

B) Se x = 4 cm e y = 7 cm, qual é o valor numérico desse perímetro.

P = 12x + 10y

x = 4cm

y = 7cm

Perímetro = 12 (4) + 10 (7)

Perímetro = 48cm + 70cm

Perímetro do retângulo = 118cm

Portanto, o valor numérico do perímetro é 118cm

7 0
3 years ago
Is 336 − –5,083 positive or negative?
Vesna [10]

Answer:

positive

Step-by-step explanation:

if you subtract a negative number, it’s the same as adding a positive number. If you add 2 positive numbers, you get a positive number, so the expression is positive.

3 0
2 years ago
Read 2 more answers
Kevin has 14 buttermilks how many buttermilk is he need to make a pancakes7​
Luda [366]

Answer:

dont know redo the question

Step-by-step explanation:

7 0
2 years ago
there are 6 girls and 8 boys in Mr. Stevenson's class the ratio of girls to boys in the class can be expressed as the simplified
Mashcka [7]

Answer: 3

Step-by-step explanation:

7 0
2 years ago
The graph of a quadratic function passes through the points (-1,0), (-2,0), and (0,2). Write the quadratic function in general f
ddd [48]

Answer:

f(x)=x^2+3x+2

Step-by-step explanation:

step 1

we have the points

(-1,0), (-2,0), and (0,2)

Plot the points

using a graphing tool

see the attached figure

The graph of a quadratic function must be a vertical parabola open upward

The vertex is a minimum

The quadratic function in general form is equal to

f(x)=ax^2+bx+c

Substitute the value of x and the value of y of each given ordered pair in the general equation and solve for a,b and c

(0,2)

For x=0, y=2

substitute

2=a(0)^2+b(0)+c

c=2

(-1,0)

For x=-1, y=0

substitute

0=a(-1)^2+b(-1)+2

0=a-b+2 ----> a=b-2 ----> equation A

(-2,0)

For x=-2, y=0

substitute

0=a(-2)^2+b(-2)+2

0=4a-2b+2 ----> equation B

we have the system

a=b-2 ----> equation A

0=4a-2b+2 ----> equation B

substitute equation A in equation B

0=4(b-2)-2b+2

solve for b

0=4b-8-2b+2

2b=6

b=3

Find the value of a

a=3-2=1

therefore

The quadratic function in general form is equal to

f(x)=x^2+3x+2

see the attached figure N 2 to better understand the problem

7 0
3 years ago
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