Answer:
Step-by-step explanation:
Given that 1/4 bucket of nuts fills 2/3 of the barrel
PART A
<u>To find the amount of nuts that fills entire basket we can put this as:</u>
- 1/4 bucket → 2/3 barrel
- x bucket → 1 barrel
<u>Use cross-multiplication to find the value of x:</u>
- x×2/3 = 1×1/4
- x = 1/4 ÷ 2/3
- x = 1/4×3/2
- x = 3/8 bucket
PART B
- Using the bucket to barrel ratio to solve the problem. Having the number of required buckets as x and considering full barrel as 1 helps to find the value of x.
Answer:
1. 
2. <u>Given</u>
3.
4. <u>Side-Side-Side (SSS) rule of congruency</u>
Step-by-step explanation:
The two column proof is presented as follows;
Statement
Reason
1.
≅
Given
2.
≅
<u>Given</u>
3.
≅
Reflexive property
4. ΔRST ≅ ΔTUR
<u>SSS rule of congruency</u>
The Side-Side-Side rule of congruency states that if three sides of one triangle are congruent to three sides of another triangle then both triangles are congruent.
<h2>
Answer:y=2x-3</h2>
Step-by-step explanation:
is called solution of a equation if
satisfies the equation.
Consider the equation
,
For point
,


So,
The point
satisfies the equation.
For point
,


So,
The point
satisfies the equation.
So,both the points satisfy the equation 
If you're using the app, try seeing this answer through your browser: brainly.com/question/2264253_______________
Evaluate the indefinite integral:

Trigonometric substitution:

then,
![\begin{array}{lcl} \mathsf{x=sin\,\theta}&\quad\Rightarrow\quad&\mathsf{dx=cos\,\theta\,d\theta\qquad\checkmark}\\\\\\ &&\mathsf{x^2=sin^2\,\theta}\\\\ &&\mathsf{x^2=1-cos^2\,\theta}\\\\ &&\mathsf{cos^2\,\theta=1-x^2}\\\\ &&\mathsf{cos\,\theta=\sqrt{1-x^2}\qquad\checkmark}\\\\\\ &&\textsf{because }\mathsf{cos\,\theta}\textsf{ is positive for }\mathsf{\theta\in \left[\dfrac{\pi}{2},\,\dfrac{\pi}{2}\right].} \end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Blcl%7D%20%5Cmathsf%7Bx%3Dsin%5C%2C%5Ctheta%7D%26%5Cquad%5CRightarrow%5Cquad%26%5Cmathsf%7Bdx%3Dcos%5C%2C%5Ctheta%5C%2Cd%5Ctheta%5Cqquad%5Ccheckmark%7D%5C%5C%5C%5C%5C%5C%20%26%26%5Cmathsf%7Bx%5E2%3Dsin%5E2%5C%2C%5Ctheta%7D%5C%5C%5C%5C%20%26%26%5Cmathsf%7Bx%5E2%3D1-cos%5E2%5C%2C%5Ctheta%7D%5C%5C%5C%5C%20%26%26%5Cmathsf%7Bcos%5E2%5C%2C%5Ctheta%3D1-x%5E2%7D%5C%5C%5C%5C%20%26%26%5Cmathsf%7Bcos%5C%2C%5Ctheta%3D%5Csqrt%7B1-x%5E2%7D%5Cqquad%5Ccheckmark%7D%5C%5C%5C%5C%5C%5C%20%26%26%5Ctextsf%7Bbecause%20%7D%5Cmathsf%7Bcos%5C%2C%5Ctheta%7D%5Ctextsf%7B%20is%20positive%20for%20%7D%5Cmathsf%7B%5Ctheta%5Cin%20%5Cleft%5B%5Cdfrac%7B%5Cpi%7D%7B2%7D%2C%5C%2C%5Cdfrac%7B%5Cpi%7D%7B2%7D%5Cright%5D.%7D%20%5Cend%7Barray%7D)
So the integral

becomes

Integrate

by parts:


Substitute back for the variable x, and you get

I hope this helps. =)
Tags: <em>integral inverse sine function angle arcsin sine sin trigonometric trig substitution differential integral calculus</em>
Answer: He should have translated the scenario as value of all dimes = value of all
Step-by-step explanation: