Answer:
<u>553.143 mi²</u>
Step-by-step explanation:
Surface Area (Cylinder) :
- 2πr (r + h)
- 2 x 22/7 x 8 (8 + 3)
- 16 x 22/7 x 11
- 176 x 22/7
- 3872/7
- <u>553.143 mi²</u>
<span>78.6 is a decimal number, you must name it with the whole part first and then the decimal part as part of tenths, hundredths or what it corresponds. In this case the whole part is 78 and the decimal part is 6/10 which is 6 tenths. Then, the number in words is sevety eight and six tenths.</span>
You would use the equation 1000(1+0.3)^x
Plug in 6 months for x
1000(1.3)^6
When you solve for that you get 4826.809 and then round to the nearest tenth I would assume so 4826.8
Hope this helps!
Answer:
hello fellow earthling
Step-by-step explanation:
D is halfway between A and B
so the coordinates of D are (2,2)
E is halfway between A and C so the coordinates of E are (-1,1)
now you need to find the gradient/slope of DE and BC using the formula:

<h3>
<u>G</u><u>r</u><u>a</u><u>d</u><u>i</u><u>e</u><u>n</u><u>t</u><u> </u><u>o</u><u>f</u><u> </u><u>D</u><u>E</u><u>:</u><u> </u></h3>
SUB IN COORDINATES OF D AND E

therefore the gradient of DE is 1/3.
<h3>
<u>G</u><u>r</u><u>a</u><u>d</u><u>i</u><u>e</u><u>n</u><u>t</u><u> </u><u>o</u><u>f</u><u> </u><u>B</u><u>C</u><u>:</u></h3>
<em>S</em><em>U</em><em>B</em><em> </em><em>I</em><em>N</em><em> </em><em>C</em><em>O</em><em>O</em><em>R</em><em>D</em><em>I</em><em>N</em><em>A</em><em>T</em><em>E</em><em>S</em><em> </em><em>O</em><em>F</em><em> </em><em>B</em><em> </em><em>A</em><em>N</em><em>D</em><em> </em><em>C</em>
<em>
</em>
therefore the gradient of BC is -2/-6 which simplifies to 1/3.
<h3>
therefore, BC and DE are parallel as they both have a gradient/slope of 1/3 and parallel lines have the same gradient</h3>