<span><span>sin(x)</span><span>(<span>sin(x)</span>+1)</span>=0</span>
implies
either <span><span>sin(x)</span>=0</span>
or <span><span>sin(x)</span>=−<span>1</span></span>
x
=
π
2
+
n
⋅
π
for all
n
ε
Z
42+7a= 7(6+a)
By noticing they both have a factor of 7, I was able to find the equation.
So the sum of 4 times a number (4 times x or 4x) and 7 (+7) is (=) 19 (19)
4x+7=19
subtract 7 from both sdies
4x=12
divide by 4
x=3
the number is 3
Radius, r = 3
The equation of a sphere entered at the origin in cartesian coordinates is
x^2 + y^2 + z^2 = r^2
That in spherical coordinates is:
x = rcos(theta)*sin(phi)
y= r sin(theta)*sin(phi)
z = rcos(phi)
where you can make u = r cos(phi) to obtain the parametrical equations
x = √[r^2 - u^2] cos(theta)
y = √[r^2 - u^2] sin (theta)
z = u
where theta goes from 0 to 2π and u goes from -r to r.
In our case r = 3, so the parametrical equations are:
Answer:
x = √[9 - u^2] cos(theta)
y = √[9 - u^2] sin (theta)
z = u
