Answer:
124 is the answer
Step-by-step explanation:
Answer: Area = 2.1 
Step-by-step explanation:
Answer:
Yes we can conclude.
Step-by-step explanation:
The sampling distribution of
can be approximated as a Normal Distribution only if:
np and nq are both equal to or greater than 10. i.e.
Both of these conditions must be met in order to approximate the sampling distribution of
as Normal Distribution.
From the given data:
n = 50
p = 0.80
q = 1 - p = 1 - 0.80 = 0.20
np = 50(0.80) = 40
nq = 50(0.20) = 10
This means the conditions that np and nq must be equal to or greater than 10 is being satisfied. So, we can conclude that the sampling distribution of pˆ is approximately a normal distribution
= 394 R 1
= 394 1/3
1183 divided by 3 equals
394 with a remainder of 1
Perimeter=2L+2W, in this case L=80+2(25) and W=170+2(25) so
P=2(L+W)=2(80+50+170+50)
P=2(350)=700m