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Alisiya [41]
3 years ago
12

Write n+5n=______ in simplest form.

Mathematics
2 answers:
pshichka [43]3 years ago
7 0
Just add them together we get 6n. 


Sphinxa [80]3 years ago
3 0
Duh 6n werent you ever been taught algebra?
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Plz help for this answer
aleksandr82 [10.1K]

Answer:

wth is up with your workbook answer is 4 i think

Step-by-step explanation:

6 0
3 years ago
Solve for x, will give brainliest
Savatey [412]
Is it 29? i’m not totally sure
7 0
3 years ago
Read 2 more answers
Find the maximum and minimum values of the function f(x,y)=2x2+3y2−4x−5 on the domain x2+y2≤100. The maximum value of f(x,y) is:
ryzh [129]

First find the critical points of <em>f</em> :

f(x,y)=2x^2+3y^2-4x-5=2(x-1)^2+3y^2-7

\dfrac{\partial f}{\partial x}=2(x-1)=0\implies x=1

\dfrac{\partial f}{\partial y}=6y=0\implies y=0

so the point (1, 0) is the only critical point, at which we have

f(1,0)=-7

Next check for critical points along the boundary, which can be found by converting to polar coordinates:

f(x,y)=f(10\cos t,10\sin t)=g(t)=295-40\cos t-100\cos^2t

Find the critical points of <em>g</em> :

\dfrac{\mathrm dg}{\mathrm dt}=40\sin t+200\sin t\cos t=40\sin t(1+5\cos t)=0

\implies\sin t=0\text{ OR }1+5\cos t=0

\implies t=n\pi\text{ OR }t=\cos^{-1}\left(-\dfrac15\right)+2n\pi\text{ OR }t=-\cos^{-1}\left(-\dfrac15\right)+2n\pi

where <em>n</em> is any integer. We get 4 critical points in the interval [0, 2π) at

t=0\implies f(10,0)=155

t=\cos^{-1}\left(-\dfrac15\right)\implies f(-2,4\sqrt6)=299

t=\pi\implies f(-10,0)=235

t=2\pi-\cos^{-1}\left(-\dfrac15\right)\implies f(-2,-4\sqrt6)=299

So <em>f</em> has a minimum of -7 and a maximum of 299.

4 0
3 years ago
What would be the answer ?
Blizzard [7]

Answer: $13

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
3xy+x=y-6 how do I solve for y in this?
Tanzania [10]

Answer:

x=y-6/3y+1

Step-by-step explanation:

3xy+x=y−6

Step 1: Factor out variable x.

x(3y+1)=y−6

Step 2: Divide both sides by 3y+1.

x(3y+1)

3y+1

=

y−6

3y+1

7 0
3 years ago
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