Help me with this plz
1 answer:
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General Idea:
To create a dot plot for a set of data we should list the data from lowest to greatest number. Then create a number line which covers all the numbers given in the data. We need to plot number of circles one above as many times based on the frequency of the data.
Applying the concept:
33, 36, 31, 37, 37, 38, 31, 37, 35, 31, 38, 32, 36, 33, 38
Listing the data in ascending order we get
31, 31, 31, 32, 33, 33, 35, 36, 36, 37, 37, 37, 38, 38, 38
We need to plot <u>three </u>circles above 31, <u>one</u> circle above 32, <u>two</u> circles above 33, <u>one</u> above 35, <u>two </u>above 36, <u>three </u>above 37, and <u>three</u> above 38.
Conclusion:
Out of the four options, the <u>correct option is B </u>because that is the only dot plot representing the given set of data.
Answer:
(2.83 , 1 , 4)
Step-by-step explanation:
Rewrite these equations in matrix form
we can write it like this,
so to solve it we need to take the inverse of the 3 x 3 matrix A then multiply it by B.
We get the inverse of matrix A,
now multiply the matrix with B
Answer:
The cost of the material for the full-sized pad is;
d) 222,750.00
Step-by-step explanation:
The parameters of the steel pad and the scale model are;
The volume of the deck = 18 yd³
The dimensions of the model of the same material = 6 feet by 4.5 feet and 4.5 inches thick
The weight of the sample, m₂ = 75 lbs
The cost of the steel, P = $55/lb
The dimensions of the sample in yards are;
6 feet = 2 yards, 4.5 feet = 1.5 yards, and 4 inches = 0. yards
The volume of the sample, V₂ = 2 yd. × 1.5 yd. × 0. yd. = (1/3) yd.³
The density of the sample material, ρ = m₂/V₂
∴ The density of the sample material, ρ = 75 lbs/((1/3)yd.³) = 225 lbs/yd³
Therefore, the density of the material of the pad, ρ = 225 lbs/yd³
The mass of the steel pad, m₁ = ρ × V₁
∴ The mass of the steel pad, m₁ = 225 lbs/yd³ × 18 yd³ = 4,050 lbs
The cost of the material for the full-sized steel pad, C = m₁ × P
∴ C = 4,050 lbs × $55/lb = $222,750