Answer:
C. 
Step-by-step explanation:
c
Answer:
6
Step-by-step explanation:
I think its 6 times greater because the length was tripled and the width was doubled thus : 3 * 2 = 6
HOPE THIS HELPED
Answer:
Quantity = 59 units
Price = $111
Step-by-step explanation:
The Demand function is given by

The Marginal cost is given by

We are asked to find the quantity and price of goods.
Firstly, obtain the Marginal revenue function from the demand function
The Total revenue is given by

The Marginal revenue is the derivative of the Total revenue,

Assuming that the monopolist maximizes profits,

Therefore, the quantity is 59 units.
The price of each good is

Therefore, the price is $111.
It wouldnt be an even number but i got 7.3
Thank you for posting your question here. I hope the answer below will help.
Vo=110 feet per second
<span>ho=2 feet </span>
<span>So, h(t) = -16t^2 +110t +2 </span>
<span>Take the derivative: h'(t) = 110 -32t </span>
<span>The maximum height will be at the inflection when the derivative crosses the x-axis aka when h'(t)=0. </span>
<span>So, set h'(t)=0 and solve for t: </span>
<span>0 = 110 -32t </span>
<span>-110 = -32t </span>
<span>t=3.4375 </span>
<span>t=3.44 seconds </span>