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xz_007 [3.2K]
3 years ago
5

What is the equation of the line whose slope is 20 and a y-intercept of 5

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
3 0
The answer is B because u always start of like that
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Write an equation for a line perpendicular to y = 5x - 4 and passing through the point (15,-1)
VLD [36.1K]

Answer:

y = -1/5 x + 2

Step-by-step explanation:

y = 5x - 4

m = 5

Slope of perpendicular = -1/5

Equation of perpendicular:

y = mx + b

y = -1/5 x + b

Use point (15, -1) for x and y, and solve for b.

-1 = -1/5(15) + b

-1 = -3 + b

b = 2

Equation of perpendicular:

y = -1/5 x + 2

4 0
2 years ago
Solve 4x+ 1 = 1 and show steps as well
Mice21 [21]
4x+1=1
    -1=-1
4x=0
4x/4=4/0
x=4


please can i have a brainliest
8 0
3 years ago
Read 2 more answers
Two given angles cannot be both..
PolarNik [594]
The right answer is congruent and complementary because they both are different from each other and different causes
4 0
3 years ago
Zeke has already written 1 page, and he expects to write 1 page for every additional hour
pshichka [43]

Answer:

50

Step-by-step explanation:

49 hours *1 page =49 pages

49 pages+1 page= 50 pages

Hope this helps! :)

6 0
3 years ago
The rate at which a duck gains weight is proportional to the difference between its adult weight and its current weight. At time
kogti [31]
DB/dt = 1/5(100 - B)
5/(100 - B) dB = dt
-5 ln (100 - B) = t + C
Since B(0) = 20, then
-5 ln (100 - 20) = C
i.e. C = -5 ln 80

Thus -5 ln (100 - B) = t - 5 ln 80
or t = 5 ln 80 - 5 ln (100 - B) = 5 ln (80 / (100 - B))

When the weight = 40 grams
t = 5 In (80 / 100 - 40) = 5 In (80 / 60) = 5 ln (4/3) = 1.438 days
Rate of weight gain = 40 / 1.438 = 27.8 grams per day

When the weight = 70 grams
t = 5 ln (80 / 100 - 70) = 5 ln (80 / 30) = 5 ln (8/3) = 4.9 days
Rate of weight gain = 70/4.9 = 14.27 grams per day.

Therefore, the duck gains weight faster when it weighs 40 grams.
6 0
3 years ago
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