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lara31 [8.8K]
3 years ago
11

Solve the equation : x^(2)+5=3(x^(2)-3)

Mathematics
1 answer:
Fittoniya [83]3 years ago
6 0

Answer:

x = ± 2

Step-by-step explanation:

Given

x² + 5 = 3x² - 3 ( subtract x² + 5 from both sides )

0 = 2x² - 8 ( add 8 to both sides )

8 = 2x² ( divide both sides by 2 )

4 = x² ( take the square root of both sides )

x = ± \sqrt{4} = ± 2

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FACTOR....<br>x^2 + 10× - 2400 = 0​
Vikki [24]

Answer:

x= -5 + 5\sqrt{97}, x= -5 - 5\sqrt{97}

Step-by-step explanation:

Since this quadratic is set to zero, we can use the quadratic formula to solve this.

x^2 + 10x - 2400 = 0​

Quadractic formula =  x= -b +- \sqrt{b^2 - 4ac} /2a

For this equation:

a= 1, b=10, c=-2400

Plug these numbers into the equation and solve.

x= -10 +- \sqrt{10^2 - 4(1)(-2400})/2(1)

x= -10 +- \sqrt{100 + 9,600}/2

x= -10 +- \sqrt{9,700}/2

x= -10 +- \sqrt{2^2 * 5^2 * 97}/2

x= -10 +- 5 * 2\sqrt{97}/2

x= -10 +- 10\sqrt{97} / 2

Divide by 2.

x= -5 +- 5\sqrt{97}

Answer:

x= -5 + 5\sqrt{97} or x= -5 - 5\sqrt{97}

5 0
3 years ago
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Answer:

The answers are in the files

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Add the coordinates together and divide by 2

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y coordinates: 0 + 2b = 2b, divided by 2 = b

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